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patriot [66]
3 years ago
7

does anyone know the questions and answers for FLVS MATH 7 grade DBA 3.00 module??? someone please help instead of telling me to

ask my instructor i can’t!
Mathematics
1 answer:
Mariana [72]3 years ago
6 0

Answer: hi

Step-by-step explanation:

hi

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Can anyone help with 1-10
Alex787 [66]

Answer:

1. E

2. A

3. B

4. AB

5. E

6. D

7. BC

8. CD

9. A

10. C

Step-by-step explanation:

6 0
3 years ago
F(x) = –22 – 9x + 20<br> Find f(9)
Nikolay [14]

Answer: -83

Step-by-step explanation:

f(9)--22+20-9*(9)=-2-81=-83

8 0
2 years ago
Read 2 more answers
A buoy marks a channel for boat navigation and bobs up and down with the motion of the waves. In the given function, represents
Nikitich [7]

Answer:

(4,-2) and (12,-2)

7 0
3 years ago
Hi, teacher I was absent these days and I didn’t understand anything about this lesson and I need help this is not count as a te
motikmotik

Given:

There are given that the cos function:

cos210^{\circ}=-\frac{\sqrt{3}}{2}

Explanation:

To find the value, first, we need to use the half-angle formula:

So,

From the half-angle formula:

cos(\frac{\theta}{2})=\pm\sqrt{\frac{1+cos\theta}{2}}

Then,

Since 105 degrees is the 2nd quadrant so cosine is negative

Then,

By the formula:

\begin{gathered} cos(105^{\circ})=cos(\frac{210^{\circ}}{2}) \\ =-\sqrt{\frac{1+cos(210)}{2}} \end{gathered}

Then,

Put the value of cos210 degrees into the above function:

So,

\begin{gathered} cos(105^{\circ})=-\sqrt{\frac{1+cos(210)}{2}} \\ cos(105^{\operatorname{\circ}})=-\sqrt{\frac{1-\frac{\sqrt{3}}{2}}{2}} \\ cos(105^{\circ})=-\sqrt{\frac{2-\sqrt{3}}{4}} \\ cos(105^{\circ})=-\frac{\sqrt{2-\sqrt{3}}}{2} \end{gathered}

Final answer:

Hence, the value of the cos(105) is shown below:

cos(105^{\operatorname{\circ}})=-\frac{\sqrt{2-\sqrt{3}}}{2}

4 0
1 year ago
Please help ( the function table)
Norma-Jean [14]
Hope this will help

8 0
3 years ago
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