The first thing we must do for this case is to define a variable.
We have then:
x: number of years before the Russo-Japanese conflict began
We write now the inequality that models the problem.
We know that the conflict began in the year 1904, therefore, all the previous years are given by:
x <1904
Answer:
an inequality in terms of x and 1904 that is true only for values of x that represent years before the start of the Russo-Japanese War is:
x <1904
Answer:
Isosceles
Step-by-step explanation:
195xy is ur lowest common denominator
Answer:
Step-by-step explanation:
Answer:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.
Step-by-step explanation:
Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:
Where
and
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
We can find a quantile in the normal standard distribution who accumulates 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64
Using this value we can set up the following equation:
And we have:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.