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ExtremeBDS [4]
3 years ago
9

What is the place value of the 3 in the number 4,397,000,000? A) Three million B) Thirty million C) Three hundred million D) Thr

ee hundred thousand
Mathematics
2 answers:
Katen [24]3 years ago
8 0
C) three hundred million. Hope this helps!

rewona [7]3 years ago
3 0
3 in the number 4,397,000,000 is 300,000,000

answer
<span>C) Three hundred million</span>
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A) Two angles are adjacent if their measures add up to 90°.
slavikrds [6]

Answer:

A) False

B) False

Step-by-step explanation:

A. Two angles whose measures add up to 90° are said to be complementary, while two angles are adjacent when formed beside each other. So, adjacent angles might be complementary or supplementary. Thus, the answer to the first part of the question is false.

B. When two angles share a side, they are said to be adjacent to each other. But supplementary angles add up to 180^{o}. Since adjacent angles might be complementary or supplementary, then the answer to the second part of the question is false.

4 0
3 years ago
GEOMETRY PLEASE HELP! THANK TOU SO MUCH :)
Anna71 [15]

Answer:

11. X=76

Step-by-step explanation:

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3 years ago
The table represent temperatures for 9 days in February. What is the average temperature?
Artist 52 [7]

Answer:sum =378 according to your new questions.

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use formula

average =sum of temperature /no of measuring day

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6 0
3 years ago
How do i turn 3/8 into a decimal
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6 0
3 years ago
Read 2 more answers
Quadratic equations and complex numbers PLEASE HELPPPP ASAP
kondor19780726 [428]

we are given

27x^3-1=0

we can also write it as

(3x)^3-(1)^3=0

now, we can use factor formula

a^3-b^3=(a-b)(a^2+ab+b^2)

we can use above formula

we get  

(3x)^3-(1)^3=(3x-1)((3x)^2+3x\times 1+(1)^2)

now, we can simplify it

27x^3-1=(3x-1)(9x^2+3x+1)

now, we can set it to 0

27x^3-1=(3x-1)(9x^2+3x+1)=0

and then we can solve for x

(3x-1)(9x^2+3x+1)=0

3x-1=0

x=\frac{1}{3}

9x^2+3x+1=0

now, we can use quadratic formula

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

now, we can plug values

and we get

x=\frac{-3\pm \sqrt{3^2-4\cdot \:9\cdot \:1}}{2\cdot \:9}

x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}

So, we will get solution as

x=\frac{1}{3},\:x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}...............Answer

5 0
3 years ago
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