Answer:
$y=(7/2)x+20$
Step-by-step explanation:
SInce the gradient of the first line is $-2/7$ then the gradien of the perpendicular line is $7/2$.
Therefore by the point slope formula the line that we are looking for is
$y-6=(7/2)(x+4)$
$y=(7/2)x + 20$
There's no if about it,

has a zero

so

is a factor. That's the special case of the Remainder Theorem; since

we'll get a remainder of zero when we divide

by

At this point we can just divide or we can try more little numbers in the function. It doesn't take too long to discover

too, so

is a factor too by the remainder theorem. I can find the third zero as well; but let's say that's out of range for most folks.
So far we have

where

is the zero we haven't guessed yet. Again we could divide

by

but just looking at the constant term we must have

so

We check

We usually talk about the zeros of a function and the roots of an equation; here we have a function

whose zeros are
Answer:
A. X-coordinate
Step-by-step explanation:
I calculated it logically
Answer:
12
Step-by-step explanation:
=> √16 • √9
=> Take square roots
=> 4 • 3
=> 12
Answer:
a = -3
Step-by-step explanation:
Solve for a:
2 (a + 5) - 1 = 3
Hint: | Distribute 2 over a + 5.
2 (a + 5) = 2 a + 10:
(2 a + 10) - 1 = 3
Hint: | Group like terms in 2 a - 1 + 10.
Grouping like terms, 2 a - 1 + 10 = 2 a + (10 - 1):
(2 a + (10 - 1)) = 3
Hint: | Evaluate 10 - 1.
10 - 1 = 9:
2 a + 9 = 3
Hint: | Isolate terms with a to the left hand side.
Subtract 9 from both sides:
2 a + (9 - 9) = 3 - 9
Hint: | Look for the difference of two identical terms.
9 - 9 = 0:
2 a = 3 - 9
Hint: | Evaluate 3 - 9.
3 - 9 = -6:
2 a = -6
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides of 2 a = -6 by 2:
(2 a)/2 = (-6)/2
Hint: | Any nonzero number divided by itself is one.
2/2 = 1:
a = (-6)/2
Hint: | Reduce (-6)/2 to lowest terms. Start by finding the GCD of -6 and 2.
The gcd of -6 and 2 is 2, so (-6)/2 = (2 (-3))/(2×1) = 2/2×-3 = -3:
Answer: a = -3