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velikii [3]
3 years ago
14

Please Help me with my math I hate functions

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
5 0
(f+g)(x)=3x^2+x+x/2-3-6=3x^2+3x/2-9
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\cos\theta=-\dfrac{4}{7}\\\\We\ know:\sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x\to\sin x=\sqrt{1-\cos^2x}\\\\subtitute:\\\\\sin x=\sqrt{1-\left(-\dfrac{4}{7}\right)^2}=\sqrt{1-\dfrac{16}{49}}=\sqrt{\dfrac{33}{49}}=\dfrac{\sqrt{33}}{7}

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5 0
3 years ago
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alina1380 [7]

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