Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
Answer:
The polynomial f(x) = x^2 - 8x - 20
I think it may be true, please correct me if i am wrong
200,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000+1
Masja [62]
Answer:
200,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,001
Step-by-step explanation:
Answer:
x= 72
Step-by-step explanation:
combine the Xs on one side and then make the denominators the same and solve
8/12X +6 = 3/4X
sub 6 on both sides
then sub 3/4 (aka. 9/12)
-1/12X= -6
multiply by reciprocal (the fraction flip-flopped)(-12) on both sides
and you get 72