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4 years ago

55 + a parentheses y * 6 parentheses - 9

1 answer:

8 0

PEMDAS. You do parentheses first, then exponents, the multiplication and division, the adding subtracting.

55 + a (y x 6) - 9

So you distribute a to y and 6 — 55 + ay x 6a -9

Subtract 9 from 55 — 46 + ay x 6a

Multiply ay and 6a (because they both have a) __ 46 + 6ay

That’s your answer.

I hope this helped!

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PLZZ HELP URGENT

Mashcka [7]

Answer:

5x + 2x.....combine like terms..... = 7x

5x + 2x....subbing in 1 7x - 1....subbing in 1

5(1) + 2(1) = 5 + 2 = 7 7(1) - 1 = 7 - 1 = 6

5x + 2x...subbing in 2 7x - 1...subbing in 2

5(2) + 2(2) = 10 + 4 = 14 7(2) - 1 = 14 - 1 = 13

5x + 2x...subbing in 3 7x - 1...subbing in 3

5(3) + 2(3) = 15 + 6 = 21 7(3) - 1 = 21 - 1 = 20

5x + 2x...subbing in 4 7x - 1....subbing in 4

5(4) + 2(4) = 20 + 8 = 28 7(4) - 1 = 28 - 1 = 27

5x + 2x...subbing in 5 7x - 1...subbing in 5

5(5) + 2(5) = 25 + 10 = 35 7(5) - 1 = 35 - 1 = 34

5x + 2x result values are 1 more then 7x - 1 result values

there are no values that will make the 2 expressions equal....

because 5x + 2x = 7x......and the other one is 7x - 1......so the 7x - 1 values will always be 1 number less...because ur subtracting one

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Simplify this question

Serhud [2]

Step-by-step explanation:

9x²/3x + 12x/3x + 1

= 3x/1 + 4/1 + 1

= 3x + 5

I hope this is true..

8 0

3 years ago

Read 2 more answers

You are planning a survey of starting salaries for recent computer science majors. In the latest survey by the National Associat

Ad libitum [116K]

Answer:

A sample size of at least 228 must be needed.

Step-by-step explanation:

We are given that in the latest survey by the National Association of Colleges and Employers, the average starting salary was reported to be $61,238. Assume that the standard deviation is $3850.

And we have to find that what sample size do we need to have a margin of error equal to $500 with 95% confidence.

As we know that the Margin of error formula is given by;

<u>Margin of error</u> = $Z_\frac{\alpha}{2} \times \frac{\sigma}{\sqrt{n} }$

where, $\alpha$ = significance level = 1 - 0.95 = 0.05 and $(\frac{\alpha}{2})$ = 0.025.

$\sigma$ = standard deviation = $3,850

n = sample size

<em>Also, at 0.025 significance level the z table gives critical value of 1.96.</em>

So, margin of error is ;

$500=1.96 \times \frac{3,850}{\sqrt{n} }$

$\sqrt{n} = \frac{1.96 \times 3,850}{500}$

$\sqrt{n}$ = 15.092

Squaring both sides we get,

n = $15.092^{2}$ = 227.8 ≈ 228

So, we must need at least a sample size of 228 to have a margin of error equal to $500 with 95% confidence.

4 0

3 years ago

Angle M 3= (6x-1) and angle m 2 = (8x+7). Find the value of x and use it to find angle m 2.

katen-ka-za [31]

Set the equation equal to each other: 6x-1 = 8x+7 then solve

4 0

4 years ago

An entrepreneur is considering the purchase of a coin-operated laundry. The current owner claims that over the past 5 years, the

Bond [772]

Answer:

a. Z-test of a population mean.

Step-by-step explanation:

The current owner claims that over the past 5 years, the average daily revenue was $675 with a standard deviation of $75.

This means that we have a large sample, which means that we can consider this to be the standard deviation for the population, which eliminates the t-test, leaving options a and c.

Population mean or proportion?

Mean, as a proportion is a value between 0 and 1, while average revenue may have lots of possible values. So the answer is given by option A.

6 0

3 years ago