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Dmitriy789 [7]
3 years ago
14

What are the corresponding parts of the figures below? Select all that apply.CBAFGE76°44°60°76°44°60°45 km50 km35 km45 km50 km35

km
Mathematics
1 answer:
Georgia [21]3 years ago
4 0

Answer:do your self it is easy

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(-5z)^3 using only positove exponents
Elena L [17]

Answer:

Shown below

Step-by-step explanation:

First allocate the power of three to every number

-5^{3}  * z^{3} = -125 * z^{3}

not sure what you mean by positive exponents, the exponents already are positive. Maybe you mean positive exponents and integers?

8 0
2 years ago
Just do a c e g and i​
marta [7]

Answer:

A, 1.57

C.0.971

E.88.3

G.3.28

I.72.9

3 0
3 years ago
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Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x3 and y = x. (10 points)
USPshnik [31]
See the graph attached.

The midpoint rule states that you can calculate the area under a curve by using the formula:
M_{n} = \frac{b - a}{2} [ f(\frac{x_{0} + x_{1} }{2}) +  f(\frac{x_{1} + x_{2} }{2}) + ... +  f(\frac{x_{n-1} + x_{n} }{2})]

In your case:
a = 0
b = 1
n = 4
x₀ = 0
x₁ = 1/4
x₂ = 1/2
x₃ = 3/4
x₄ = 1

Therefore, you'll have:
M_{4} = \frac{1 - 0}{4} [ f(\frac{0 +  \frac{1}{4} }{2}) +  f(\frac{ \frac{1}{4} + \frac{1}{2} }{2}) +  f(\frac{\frac{1}{2} + \frac{3}{4} }{2}) + f(\frac{\frac{3}{4} + 1} {2})]
M_{4} = \frac{1}{4} [ f(\frac{1}{8}) +  f(\frac{3}{8}) +  f(\frac{5}{8}) + f(\frac{7}{8})]

Now, to evaluate your f(x), you need to look at the graph and notice that:
f(x) = x - x³

Therefore:
M_{4} = \frac{1}{4} [(\frac{1}{8} - (\frac{1}{8})^{3}) + (\frac{3}{8} - (\frac{3}{8})^{3}) + (\frac{5}{8} - (\frac{5}{8})^{3}) + (\frac{7}{8} - (\frac{7}{8})^{3})]

M_{4} = \frac{1}{4} [(\frac{1}{8} - \frac{1}{512}) + (\frac{3}{8} - \frac{27}{512}) + (\frac{5}{8} - \frac{125}{512}) + (\frac{7}{8} - \frac{343}{512})]

M₄ = 1/4 · (2 - 478/512)
     = 0.2666

Hence, the <span>area of the region bounded by y = x³ and y = x</span> is approximately 0.267 square units.

6 0
4 years ago
Communicate mathematical ideas why might you want to use the commutative property to change the order of the integers in the fol
Kruka [31]

I might want to use the commutative property to change the order of the integers in the following sum before adding the given expression

"-80 + (-173)+(-20)"

As commutative property states that " Changing the order of addends does not change the sum" which means if we add 'a' to 'b' or 'b' to 'a', we will get the same answer.

Therefore, here if we add '-80' to '-173' or '-173' to '-80' , or if we add '-173' to '-20' or '-20' to '-173' , we will get the same answer.

Therefore, we might use commutative property to change the order the of integers in the following sum.

7 0
3 years ago
What is the answer for 2.7cm=m
SIZIF [17.4K]
0.027 in meters!!!!!!
6 0
3 years ago
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