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olchik [2.2K]
3 years ago
8

How do you simply algebra 10+3c+5d-7c+d

Mathematics
1 answer:
Vitek1552 [10]3 years ago
5 0

Answer:

-4c + 6d + 10.

Step-by-step explanation:

<em>Group like terms</em>  -   3c - 7c + 5d + d + 10

<em>Add/Subtract   -    </em>-4c + 6d +1 0

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I think of a number, add 8 to it and the result is 14. Find the number​
Leya [2.2K]

Answer:

6

Step-by-step explanation:

The equation for this would be:

n+8=14, since we are adding 8 to a number and getting 14

To solve, isolate the variable n, by subtracting 8 from both sides

n+8=14

n+8-8=14-8

n=6

The number is 6

3 0
3 years ago
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3. 1 + sec2x sin2x = sec2x
IgorLugansk [536]

Answer:

Answer is on pic

Step-by-step explanation:

I hope it's helpful!

7 0
3 years ago
Given the diagram at the right, which of the following must be true?
S_A_V [24]

Answer:

it is B. sxf = gxt.

Step-by-step explanation:



5 0
3 years ago
A) write a relation for perimeter of a square with side length n centimetres
Artist 52 [7]
The perimeter of a square is equal to the side length times 4.

The equation is P = 4S, with P being the perimeter, and S being a side. 

Also, to get the length of a side from the perimeter, just divide the perimeter by 4.

To have it in centimeters, just add cm to the end of your answer!
5 0
3 years ago
g In American roulette, the wheel has the 38 numbers, 00, 0, 1, 2, ..., 34, 35, and 36, marked on equally spaced slots. If a pla
earnstyle [38]

Answer:

The expected value for the player to play one time is -$0.05.

Step-by-step explanation:

The expected value of a random variable <em>X</em> is given by the formula:

E(X)=\sum x\cdot P(X)

The American roulette wheel has the 38 numbers, {i = 00, 0, 1, 2, ..., 34, 35, and 36}, marked on equally spaced slots.

The probability that the ball stops on any of these 38 numbers is same, i.e.

P (X = i) = \frac{1}{38}.

It is provided that a a player bets $1 on a number.

If the player wins, the player keeps the dollar and receives an additional $35.

And if the player losses, the dollar is lost too.

So, the probability distribution is as follows:

<em>     X </em>: $35      -$1

P (<em>X</em>) :   \frac{1}{38}         \frac{37}{38}  

Compute the expected value of the game as follows:

E(X)=\sum x\cdot P(X)

         =[\$35\times \frac{1}{38}]+[-\$1\times \frac{37}{38}]\\\\=\frac{\$35-\$37}{38}\\\\=-\frac{\$2}{38}\\\\=-\frac{1}{19}\\\\=-0.052632\\\\\approx -\$0.05

Thus, the expected value for the player to play one time is -$0.05.

7 0
3 years ago
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