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2 years ago

Which expression is equivalent to (2g^5)^3/(4h^2)^3

Mathematics

2 answers:

9966 [12]2 years ago

7 0

$\cfrac{(2g^5)^3}{(4h^2)^3} = \cfrac{2^3 \cdot g^{5\cdot3}}{4^3 \cdot h^{2\cdot3}} = \cfrac{8 g^{15}}{64 h^{6}} =\cfrac{g^{15}}{8h^{6}}$

First option

gayaneshka [121]2 years ago

4 0

Answer:

Its A on Edge. g^15/8h^6

Step-by-step explanation:

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CAN SOMEONE MULTIPLY THIS PLEASE, ITS URGENT

____ [38]

Let's factorise it :

$\: {\qquad \dashrightarrow \sf ( {x}^{3} - 5)(x + 3) }$

$\: {\qquad \dashrightarrow \sf {x}^{3} (x + 3) + [-5(x + 3)] }$

Using Distributive property we get :

$\: {\qquad \dashrightarrow \sf {x}^{3} + {3x}^{3} + ( - 5x - 15) }$

$\: {\qquad \dashrightarrow \sf {x}^{3} + {3x}^{3} - 5x - 15 }$

$\: {\qquad \dashrightarrow \sf 4{x}^{3} - 5x - 15 }$

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Therefore,

$\: {\qquad \dashrightarrow \sf ( {x}^{3} - 5)(x + 3) =4{x}^{3} - 5x - 15}$

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1 year ago

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kirza4 [7]

Answer:

Step-by-step explanation:

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2 years ago

Select all ratios equivalent to 1:8.

DochEvi [55]

Answer: 2:16 - 3:24 - 4:32 - 5:40 - 6:48 - 7:56 - 8:64 // just keep adding each side to its own side

Step-by-step explanation:

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2 years ago

Can someone plot this for me, can’t tell if i’m wrong.

vaieri [72.5K]

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2 years ago

Read 2 more answers

Find the median of the data.

kipiarov [429]

Answer:

92.5

Step-by-step explanation:

The data given:

93, 81, 94, 71, 89, 92, 94, 99

Put the data in the ascending order:

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Since the data size is even, the median is the average of middle two:

median = (92 + 93)/2 = 92.5

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2 years ago