Step-by-step explanation:
You have found a function r(V(t)). We can see that this function is a one variable function. The variable is time.
So in this specific function we can call r(v(t)), r(t).
So:
![r(t) = \sqrt[3]{ \frac{3 \times (10 + 20t)}{4\pi} }](https://tex.z-dn.net/?f=r%28t%29%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%20%5Ctimes%20%2810%20%2B%2020t%29%7D%7B4%5Cpi%7D%20%7D%20)
If α is the moment that the radius is 10 inches and since the function above gives radius in inches we have to solve the equation:

Which is the same as:
![\sqrt[3]{ \frac{3 \times (10 + 20 \alpha )}{4\pi} } = 10 \\ \frac{3 \times (10 + 20 \alpha )}{4\pi} = 1000 \\ (10 + 20 \alpha ) = \frac{4000\pi}{3} \\ 20 \alpha = \frac{(4000\pi - 30)}{3} \\ \alpha = \frac{(4000\pi - 30)}{60}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%20%5Ctimes%20%2810%20%2B%2020%20%5Calpha%20%29%7D%7B4%5Cpi%7D%20%7D%20%20%3D%2010%20%5C%5C%20%20%5Cfrac%7B3%20%5Ctimes%20%2810%20%2B%2020%20%5Calpha%20%29%7D%7B4%5Cpi%7D%20%20%3D%201000%20%5C%5C%20%2810%20%2B%2020%20%5Calpha%20%29%20%3D%20%20%5Cfrac%7B4000%5Cpi%7D%7B3%7D%20%20%5C%5C%2020%20%5Calpha%20%20%3D%20%20%5Cfrac%7B%284000%5Cpi%20-%2030%29%7D%7B3%7D%20%5C%5C%20%20%5Calpha%20%20%3D%20%20%5Cfrac%7B%284000%5Cpi%20-%2030%29%7D%7B60%7D%20)
12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc
Answer:
Step-by-step explanation:
abc=80, abm= 100
acb= 40, acn= 140
angle a = 60
x=80, y=40
Answer:
27.11514 pi
Step-by-step explanation:
Given is a function exponential as

The region bounded by the above curve, y =0 , x=-2 x =1 is rotated about x axis.
The limits for x are -2 and 1
The volume when rotated through x axis is found by

Here a = -2 and b =1
volume = 
=
Hi Im A senior in high school are you sure you did this question right? it seems to make no sense. if you wrote it wrong please fix it and i can help you.
Thank you for posting your answer on brainly have a blessed day