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andriy [413]
3 years ago
13

HELP FAST FAST FAST FAST PLS ILL LOVE YOU FORVER. Greta is putting a 20 foot fence around her pool. She uses all the border to m

ake four sections that are the same length. Which expression does NOT equal the length of one of these sections in feet?

Mathematics
1 answer:
dezoksy [38]3 years ago
8 0

Answer:

20 over 4 llllllllll<em /><em />

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A ramp is used to load suitcases on an airplane. If the cargo door is 7 feet from the ground and the angle formed by the end of
melisa1 [442]

Answer: 16.56\ ft

Step-by-step explanation:

You must draw a right triangle as the one attached, where "x" is the lenght  in feet of the ramp.

You need to use the following Trigonometric Identity:

sin\alpha=\frac{opposite}{hypotenuse}

In this case you can identify that:

\alpha =25\°\\\\opposite=7\\\\hypotenuse=x

Now you must substitute these values into sin\alpha=\frac{opposite}{hypotenuse}:

sin(25\°)=\frac{7}{x}

Finally, you must solve for "x" in order to find its value.

This is:

sin(25\°)=\frac{7}{x}\\\\xsin(25\°)=7\\\\x=\frac{7}{sin(25\°)}\\\\x=16.56

6 0
3 years ago
Find the value of C.
Elan Coil [88]

Answer:

C

Step-by-step explanation:

We already know that a right angle is 90° and where C is in the picture shows us an obtuse angle making it beleive that it must be above 90°, which leaves us with C as our final answer and is the only answer that makes sense to be correct. Hopefully this helped you.

5 0
3 years ago
I need help with this problem, if anyone could help ASAP, that would be much appreciated. In the figure below, mROP = 125° Find
VARVARA [1.3K]

Answer:

mRP = 125°

mQS = 125°

mPQR = 235°

mRPQ = 305°

Step-by-step explanation:

Given that

  • mROP = 125°
  • ∠ROP is a central angle

Then:

  • measure of arc RP, mRP = mROP = 125°

Given that

  • ∠QOS and ∠ROP are vertical angles

Then:

  • mQOS = mROP = 125°
  • measure of arc QS, mQS = mROP = 125°

Given that

  • ∠QOR and ∠SOP are vertical angles

Then:

  • mQOR = mSOP

Given that

  • The addition of all central angles of a circle is 360°

Then:

mQOS + mROP + mQOR + mSOP = 360°

250° + 2mQOR = 360°

mQOR = (360°- 250°)/2

mQOR = mSOP = 55°

And (QOR and SOP are central angles):

  • measure of arc QR, mQR = mQOR = 55°
  • measure of arc SP, mSP = mSOP = 55°

Finally:

measure of arc PQR, mPQR = mQOR + mSOP + mQOS = 55° + 55° + 125° = 235°

measure of arc RPQ, mRPQ = mROP + mSOP + mQOS = 125° + 55° + 125° = 305°

6 0
3 years ago
Use inverse operations to solve the equation <br><br> a - 5/6 = - 3 2/3
larisa [96]

Answer:

sorry if I'm wrong but I think its a=1/6

4 0
3 years ago
Read 2 more answers
If angle JKM= 15x-48 and angle L= 5x+12 and angle M= 40, find angle MKL
horrorfan [7]
JKM = M + L
15x - 48 = 40 + 5x + 12
10x - 48 = 52
10x = 100
x = 10
JKM = 15(10) - 48 = 102

180 = JKM + MKL
180 = 102 + MKL
MKL = 180 - 102 = 78
5 0
3 years ago
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