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kondor19780726 [428]
3 years ago
9

Lactic acid is a common by-product of cellular respiration and is often said to cause the "burn" associated with strenuous activ

ity. a 25.0-ml sample of 0.100 m lactic acid (hc3h5o3, pka 5 3.86) is titrated with 0.100 m naoh solution. calculate the ph after the addition of 0.0 ml, 4.0 ml, 8.0 ml, 12.5 ml, 20.0 ml, 24.0 ml, 24.5 ml, 24.9 ml, 25.0 ml, 25.1 ml, 26.0 ml, 28.0 ml, and 30.0 ml of the naoh. plot the results of your calculations as ph versus milliliters of naoh added.
Chemistry
1 answer:
Llana [10]3 years ago
7 0
I honestly dont know this one but ill ask my brother and he might know
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What is Bohr's atomic model? ​
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Answer:

The Bohr model and all of its successors describe the properties of atomic electrons in terms of a set of allowed (possible) values. Atoms absorb or emit radiation only when the electrons abruptly jump between allowed, or stationary, states. Direct experimental evidence for the existence of such discrete states was obtained (1914) by the German-born physicists James Franck and Gustav Hertz.

Explanation:

5 0
3 years ago
When phenolphthalein indicator is added to a colorless solution with a pH of 10, a student observes and concludes that the teste
madam [21]

Answer:

3.  turns pink and is basic

Explanation:

Phenolphthalein is a pH indicator that remains colorless in acidic solutions, but in basic solutions it turns pink at a pH equal to 10.

Phenolphthalein is a weak acid that loses H+ cations in solution. The phenolphthalein molecule is colorless, while the phenolphthalein-derived anion is pink. When a base is added, phenolphthalein loses H+, forming the anion and causing it to turn pink. The color change cannot be explained only on the basis of deprotonation, a structural change occurs with the appearance of a ketoenolic tautomerism.

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3 years ago
What is the definition of thermal equilibrium
bixtya [17]
It means the relationship between two systems connected only by a diathermic wall.
7 0
3 years ago
Read 2 more answers
Which is a balanced chemical equation? A. C7H16 + 5O2 6CO2 + 4H2O B. C7H16 + 11O2 7CO2 + 8H2O C. C7H16 + 14O2 7CO2 +5H2O D. C7H1
nadya68 [22]

Answer:

\boxed{\text{B.}}

Explanation:

B.

\rm C$_7$H_{16}$ + 11O$_2$ $\longrightarrow \,$ 7CO$_2$ + 8H$_2$O

BALANCED. 7C, 16H, and 22O on each side of equation.

A.

\rm C$_7$H$_{16}$ + 5O$_2$ $\longrightarrow \,\rm 6CO$_2$ + 4H$_2$O

NOT BALANCED. 7C on left and 6C on right.

C.

\rm C$_7$H$_{16}$ + 14O$_2$ $\longrightarrow \,$ 7CO$_2$ + 5H$_2$O

NOT BALANCED. 16H on left and 10H on right.

D.

\rm C$_7$H$_{16}$ + 22O$_2$ $\longrightarrow \, $ 14CO$_2$ + 16H$_2$O

NOT BALANCED. 7C on left and 14C on right.

3 0
3 years ago
How to balance lead and silver acetate yields lead (||) acetate and silver
arsen [322]
The given elements put into an equation using their symbols  are as follows:
Pb + AgC_{2}H_{3}O_{2} = Pb(II){(C_{2}H_{3}O_{2})_2} + Ag

Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb + AgC_{2}H_{3}O_{2} = Pb(II){(C_{2}H_{3}O_{2})_2} + Ag

Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb + 2AgC_{2}H_{3}O_{2} = Pb(II){(C_{2}H_{3}O_{2})_2} + Ag

Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb + 2AgC_{2}H_{3}O_{2} = Pb(II){(C_{2}H_{3}O_{2})_2} + 2Ag

That is your final equation

The coefficients are 2 + 2 = 1 + 2
3 0
3 years ago
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