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ElenaW [278]
4 years ago
7

Malachi bought a new fishing rod. The regular price of the fishing rod was $125.99. He bought it on sale with a 15% discount. Sa

les tax of 3% is applied to the discounted total. What was the sale price with tax of Malachi's fishing rod to the nearest cent?
Mathematics
1 answer:
Volgvan4 years ago
8 0

If the discount is 15 percent, he still pays (100-15) or 85%

125.99 * 85%

125.99 * .85 = 107.09  is the price he pays for the rod

107.09 * .03 =3.21 is the sales tax

107.09+3.21=110.30 is the price of the rod with the discount and the tax

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Jennifer walks 9 blocks south and 5 blocks west. Approximately how many blocks is she from home if she were to take a direct pat
rodikova [14]

9514 1404 393

Answer:

  10.3

Step-by-step explanation:

Assuming the blocks are square, we can use the Pythagorean theorem to find the diagonal distance.

 d² = 9² +5² = 81 +25 = 106

 d = √106 ≈ 10.3

Jennifer is about 10.3 blocks from home.

5 0
3 years ago
I need help with this one, NOW!
creativ13 [48]

Answer:

It is 25 degrees.

Step-by-step explanation:

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3 years ago
Which properties justify the steps taken to solve the system?
NNADVOKAT [17]

Your Welcome!!  

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4 0
3 years ago
Read 2 more answers
A second particle, Q, also moves along the x-axis so that its velocity for 0 £ £t 4 is given by Q t cos 0.063 ( ) t 2 v t( ) = 4
Vladimir79 [104]

Answer:

The time interval when V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

The distance is 106.109 m

Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

V_Q(t) \geq 60    between   0 \leq t \leq 4

The schematic free body graphical representation of the above illustration was attached in the file below and the point when V_Q(t) \geq 60  is at 4 is obtained in the parabolic curve.

So, V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

Taking the integral of the time interval in order to determine the distance; we have:

distance = \int\limits^{3.519}_{1.866} {V_Q(t)} \, dt

= \int\limits^{3.519}_{1.866} {45\sqrt{t} cos(0.063 \ t^2)} \, dt

= By using the Scientific calculator notation;

distance = 106.109 m

4 0
3 years ago
5z - 3 >7 or 4z -6< - 10
tiny-mole [99]

Answer:

4z -6< - 10= Z= < -1

5z - 3 >7= Z=< 2

Step-by-step explanation:

5 0
3 years ago
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