How to solve 3 variable systems
1 answer:
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Answer: 0.31
Step-by-step explanation:
Let A denotes the event that the students report drinking alcohol and B denotes the students report using some type of tobacco product .
Given : P(A) =0.84 ; P(B)=0.33 and P(A∪B)=0.86
We know that
Then, the probability that the student both drunk alcohol and used tobacco in the past month is given by :-
Hence, the probability that the student both drunk alcohol and used tobacco in the past month = 0.31
Answer: " -2y³ + 3y²<span> + 27y " .
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Refer to the completed chart below (image attached).</span>
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Using the completed chart below (image attached), we can write out the terms:
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y³ − 3y³ + 9y² + 3y² − 9y² + 27y ;
Then, we can combine the "like terms" ;
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y³ − 3y³ = -2y³ ;
+9y² + 3y² − 9y² = + 3y² ;
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to get: -2y³ + 3y² ; and bring down the "+27y" ;
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Answer: " -2y³ + 3y²<span> + 27y " . </span>Refer to chart below (image attached).
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_______________________________________________________
Refer to the completed chart below (image attached).</span>
_______________________________________________________
Using the completed chart below (image attached), we can write out the terms:
__________________________________________________
y³ − 3y³ + 9y² + 3y² − 9y² + 27y ;
Then, we can combine the "like terms" ;
__________________________________________
y³ − 3y³ = -2y³ ;
+9y² + 3y² − 9y² = + 3y² ;
___________________________________________________________
to get: -2y³ + 3y² ; and bring down the "+27y" ;
___________________________________________________________
Answer: " -2y³ + 3y²<span> + 27y " . </span>Refer to chart below (image attached).
___________________________________________________________
Hello,
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Maybe i have not understood "into".