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olganol [36]
3 years ago
14

Alberts hair was 5 centimeters long after his last haircut and it grows 4 cm every year. How many years will it take until Alber

ts hair is 33 cm long
Mathematics
2 answers:
Lera25 [3.4K]3 years ago
5 0
The answer is 7. The answer is 7 because 33-5=28, and 28/4=7, so the answer is that it will take 7 years for his hair to grow to 33 centimeters. 
andrew11 [14]3 years ago
4 0
Here's how I did this problem.

Alberts hair is already 5 centimetres long. We know that his hair grows by 4 centimetres every year, and we have to figure out how long it takes until his hair is 33 centimetres. So, it's easier to subtract 33 from 5, and see if that result is divisible by 4, and it is, because 33-5 is 28, which goes into 4, 7 times. (4*7 = 28), so it will take Albert 7 years, until his hair is 33 centimetres long.

Hope this helped.
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4 0
3 years ago
Find the values of x and y ​
icang [17]

Answer:

x=15\\y=38

Step-by-step explanation:

By definition, the sum of the interior angles of a triangle is 180 degrees.

You can observe that the  given triangle has an angle that measures 90 degrees and it also has two equal sides.This means that  the other two angles are equal.

Knowing this, you can conclude that the triangle  is an Isosceles Right Triangle and the other angles measure 45 degrees each.

Therefore, now you know that:

3x=45

Solving for "x", you get that its value is:

x=\frac{45}{3}\\\\x=15

And for the other angle:

y+7=45

Solving for "y", you get that its value is the following:

y=45-7\\\\y=38

8 0
3 years ago
I WILL GIVE 15 POINTS! The park road is 6 kilometers long. The distance from the East Entrance to the Nature Center is 8 kilomet
natali 33 [55]

Answer:

48 km.

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Multiply 6 and 8, you get 48.

7 0
3 years ago
Put these in order of size from smallest to largest: 7/4 , 74% , 7.4 , 4/7 , 70.4
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8 0
3 years ago
Log16^*+log4^*+log2^*=7​
ale4655 [162]

Answer:

x = 16

Step-by-step explanation:

Given

log_{16}(x) + log_4(x) + log_2(x) = 7

Required

Solve for x

log_{16}(x) + log_4(x) + log_2(x) = 7

Change base of 16 and base of 4 to base 2

\frac{log_2(x)}{log_2(16)} + \frac{log_2(x)}{log_2(4)} + log_2(x) = 7

Express 16 and 4 as 2^4 and 2^2 respectively

\frac{log_2(x)}{log_2(2^4)} + \frac{log_2(x)}{log_2(2^2)} + log_2(x) = 7

The above can be rewritten as:

\frac{log_2(x)}{4log_22} + \frac{log_2(x)}{2log_22} + log_2(x) = 7

log_22 = 1

So, we have:

\frac{log_2(x)}{4*1} + \frac{log_2(x)}{2*1} + log_2(x) = 7

\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x) = 7

Multiply through by 4

4(\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x)) = 7 * 4

log_2(x) + 2}log_2(x) + 4log_2(x) = 28

7log_2(x) = 28

Divide through by 7

\frac{7log_2(x)}{7} = \frac{28}{7}

log_2(x) = 4

Apply the following law of logarithm:

<em>If </em>log_ab = c<em> </em><em>Then </em>b = a^c<em></em>

So, we have:

x = 2^4

x = 16

6 0
3 years ago
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