Given:
μ = $3.26 million, averaged salary
σ = $1.2 million, standard deviation
n = 100, sample size.
Let x = random test value
We want to determine P(x>4).
Calculate z-score.
z = (x - μ)/ (σ/√n) = (4 - 3.26)/(1.2/10) = 6.1667
From standard tables,
P(z<6.1667) = 1
The area under the distribution curve = 1.
Therefore
P(z>6.1667) = 1 - P(z<=6.1667) = 1 - 1 = 0
Answer: The probability is 0.
I think the answer is 31.75
Length of the median would be: a+b / 2 = 19+38 / 2 = 57/2 = 28.5
Yes and thank you for the points
