Answer:
33/20
Step-by-step explanation:
1/12 - 1/15 = 5/60 - 4/60 = 1/60
d = 1/60
a_n = a_1 + d(n - 1)
a_11 = 1/15 + (1/60)(11 - 1)
a_11 = 1/15 + 1/6
a_11 = 4/60 + 10/60
a_11 = 14/60
a_11 = 7/30
a_12 = 14/60 + 1/60
a_12 = 15/60
a_12 = 1/4
s_n = n(a_1 + a_n)/2
s_11 = 11(1/15 + 7/30)/2
s_11 = 11(2/30 + 7/30)/2
s_11 = 11(9/30)/2
s_11 = 99/60
s_11 = 33/20
Answer:
1850
Step-by-step explanation:
The problem is asking you how many kids (predicted by the superintendent) will buy lunches for 1-2 days. Since you know the percentage predicted and the student amount, just multiply as a decimal (convert by putting the number over 100 as a fraction.)
5000*0.37=1850
Attendance with the higher ticket price is ...
... $1750/$7 = 250
So the percentage change in attendance is ...
... change = (new - original)/original × 100%
... = (250 -300)/300 × 100% = -1/6×100% ≈ -17%
Answer:
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Answer is B: 150
write two equations
r+s=190
4r+3s=720
solve by substitution
the get r=150 s=40