I don't know if there are any options....so I did reasearch I found the question and I believe it is graph 4 because it intersects at (1,5)!
2g - 2h = b + 4
2g = b + 4 + 2h
g = (b + 4 + 2h) / 2
Step-by-step explanation:
the solutions for a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
a = 1
b = -4
c = k
x = (4 ± sqrt(16 - 4k))/2 = 2 ± sqrt(4 - k)
x1 = 2 + sqrt(4 - k)
x2 = 2 - sqrt (4 - k)
x1 = 2 + x2
2 + sqrt(4 - k) = 2 + 2 - sqrt(4 - k)
2×sqrt(4 - k) = 2
sqrt(4 - k) = 1
4 - k = 1
k = 4 - 1 = 3
x1 = 3
x2 = 1
(v-4t)(v+nt)
=v^2+vnt-4tv-4nt^2