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Andru [333]
3 years ago
8

I need help with this

Mathematics
2 answers:
masya89 [10]3 years ago
8 0
Hello there! With finding the area of the rectangle in this scenario, we have to multiply binomials by doing distribution or in this case, the FOIL method. This means, multiply the terms by the first terms of each parenthesis, the outer terms of the parenthesis, inner terms of the parenthesis, and the last terms in both parenthesis. It's a bit like regular distribution. Set it up like this:

(4x - 7)(x + 3)

Now, multiply the terms. 4x * x is 4x². 4x * 3 is 12x. -7 * x is -7x. -7 * 3 is -21. Combine like terms in order to get 4x² + 5x - 21. The answer is D.

Note: If there is a negative in front of the number you are multiplying, you incorporate the negative in that number. x² is there, because two x's are being multiplied together. Be sure to incorporate these steps and solve the right way and be aware of the symbols. Otherwise, you might make a mistake.
rodikova [14]3 years ago
5 0
You need to expand (4x-7)(x+3), multiplying each term in the first bracket by each term in the second bracket, in order to get 4x^2+5x-21. Hope that helps!
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8:45

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Michelle's class is handing out balloon arrangement consisting of 4 balloons each each balloon has and equally likely chance of
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Answer:

The answer is 1/30 or 0.0333333...

Step-by-step explanation:

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3 years ago
The coordinates of the endpoints of AB and CD are A(2,
Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

m= \frac{y_2-y_1}{x_2-x_1}

Formula to Find Distance between two points

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

mAB ( represents , Slope of AB )

1. mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}

2. mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}

3. mCD=\frac{5-2}{6-5}=\frac{3}{1}=3

4. AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

5. BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

mAC = mBC  , and C is common point , hence these three are collinear points  making a straight line whole slope is -\frac{1}{3}

mAB=-\frac{1}{3}

mCD=3

mAB \times mCD = -\frac{1}{3} \times 3 = -1

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

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The answer should be D if I’m wrong
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Answer:

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