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Andreyy89
3 years ago
15

Classify the following triangle.Check all that apply.

Mathematics
1 answer:
zysi [14]3 years ago
6 0
Perhaps you can send a picture of the problem so I can help you?
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Write an equation of the line parallel to x+2y=-4 through the point (-8,5)<br> show all work
scoundrel [369]

Answer:

The equation of the parallel line would be y = -1/2x + 1

Step-by-step explanation:

To start we need to find the slope of the original  line. We can do that by solving for y.

x + 2y = -4

2y = -x - 4

y = -1/2x - 2

Since the slope of the original line is -1/2 and parallel lines have the same slope, we know the new line will also have -1/2 slope. Now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = -1/2(x + 8)

y - 5 = -1/2x - 4

y = -1/2x + 1

4 0
3 years ago
Help help help help help help help help help help help help help​
kvasek [131]
Yeah I just took the text it’s false
3 0
3 years ago
Solve 13+x&gt;11. Enter your answer as an equality
Wittaler [7]

Answer:

x>-2

Step-by-step explanation:

13+x>11

Subtract 13 from each side

13-13+x>11-13

x>-2

5 0
3 years ago
Type the correct answer in the box use/ for the fraction bar
Zarrin [17]

Answer:

see explanation

Step-by-step explanation:

given the 2 equations

y = x² - 2x - 19 → (1)

y + 4x = 5 → (2)

substitute y = x² - 2x - 19 into (2)

x² - 2x - 19 + 4x = 5 ( subtract 5 from both sides )

x² + 2x - 24 = 0 ← in standard form

(x + 6)(x - 4) = 0 ← in factored form

equate each factor to zero and solve for x

x + 6 = 0 ⇒ x = - 6

x - 4 = 0 ⇒ x = 4

substitute each value of x into (1) for corresponding y- coordinate

x = - 6 : y = (- 6)² - 2(- 6) - 19 = 36 + 12 - 19 = 29 ⇒ (- 6, 29)

x = 4 : y = 4² - 2(4) - 19 = 16 - 8 - 19 = - 11 ⇒ (4, - 11)

the solutions are (- 6, 29), (4, - 11)


6 0
3 years ago
What are the solutions to this equation?
ziro4ka [17]

 

\displaystyle\\(x-4)^2=49\\\\(x-4)^2-49=0\\\\(x-4)^2-7^2=0\\\\(x-4-7)(x-4+7)=0\\\\(x-11)(x+3)=0\\\\x-11 = 0~~~\text{or}~~~x+3=0\\\\x-11=0~~~\implies~~~\boxed{x_1=11}\\\\x+3=0~~~\implies~~~\boxed{x_2=-3}\\\\\boxed{\bf The~solutions~are:~~x =11~~\text{or}~~x =-3}



8 0
3 years ago
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