Answer:
<u>43%</u>
Step-by-step explanation:
mark me as brainliest please
Answer:
(-1, 4)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
10x + 6y = 14
-x - 6y = -23
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Elimination</em>
- Add 2 equations together: 9x = -9
- Divide 9 on both sides: x = -1
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: -x - 6y = -23
- Substitute in <em>x</em>: -(-1) - 6y = -23
- Multiply: 1 - 6y = -23
- Subtract 1 on both sides: -6y = -24
- Divide -6 on both sides: y = 4
Answer:
I think b
Step-by-step explanation:
Answer:
the answer is A just tool the quiz lesson 5 hyperbolas Algebra 2B unit 5 these are the correct answers
1.A
2.B
3.D
4.A
5.B
6.D
7.A
hopes this helps everyone
Answer: 644,800
Step-by-step explanation:
This can also be solved using the terms of Arithmetic Progressions.
Let the 13 years be number of terms of the sequences (n)
Therefore ;
T₁₃ = a + ( n - 1 )d , where a = 310,000 and d = 9% of 310,000
9% of 310,000 = 9/100 x 310,000
= 27,900
so the common difference (d)
d = 27,900
Now substitute for the values in the formula above and calculate
T₁₃ = 310,000 + ( 13 - 1 ) x 27,900
= 310,000 + 12 x 27,900
= 310,000 + 334,800
= 644,800.
The population after 13 years = 644,800.
