All categories

3 years ago

The rule r y-axis R 0,90^ (x,y) is applied to triangle ABC . Which triangle shows the final image?

Mathematics

2 answers:

Zarrin [17]3 years ago

7 0

Answer: 1

Step-by-step explanation:

NemiM [27]3 years ago

5 0

Answer:

Step-by-step explanation:

Given triangle ABC with vertices at points A(2,-4), B(4,-4) and C(4,-2).

1. Rotate this triangle anticlockwise by 90° angle over the origin. This rotation has the rule

$(x,y)\rightarrow (-y,x),$

then

$A(2,-4)\rightarrow A'(4,2)\\ \\B(4,-4)\rightarrow B'(4,4)\\ \\C(4,-2)\rightarrow C'(2,4)$

2. Reflect triangle A'B'C' across the y-axis. This reflection has the rule

$(x,y)\rightarrow (-x,y),$

then

$A'(4,2)\rightarrow A''(-4,2)\\ \\B'(4,4)\rightarrow B''(-4,4)\\ \\C'(2,4)\rightarrow C''(-2,4)$

These are vertices of triangle 1

You might be interested in

In the largest clinical trial ever conducted, 401,974 children were randomly assigned to two groups. The treatment group consis

BARSIC [14]

Answer:

The requirements for the hypothesis test does satisfied the method for testing the claim that from two population proportions the rate of polio is less for children given the salk vaccine.

Step-by-step explanation:

The percentage of children in the treatment group was:

(201229/401974)*100 = 49.9%

The percentage of children given placebo was:

(200745/401974)*100 = 50.1%

The percentage of children that developed polio in the treatment group:

(33/200745)*100 = 0.0164%

The percentage of children that developed polio in the placebo group:

(115/201229)*100 = 0.0571%

The percentage difference between the two group:

((0.0571-0.0164)/0.0571) = 61.62%

Therefore:

The amount of children used for each group was almost divided into half of the total amount of children. The test revealed although very small percentages of the both group developed polio, 68.62% more children given placebo than the children that was given the salk vaccine. Therefore, the study shows that the rate of polio is less for children given the salk vaccine and the the hypthesis test is satisfied.

6 0

3 years ago

Please help! Will give Brainliest and 20 POINTS!

jarptica [38.1K]

Your answer would be the first on because when you set up your equation you can find 4 by dividing 42,980 by 10 4 times wich will give you 10^4 when you divide exponents you subtract so iwill look like this....

5x10^6
----------= 1.25x10^2
4x10^4

3 0

4 years ago

Let f(x) = [infinity] xn n2 n = 1 . Find the intervals of convergence for f. (Enter your answers using interval notation.) Incor

sveta [45]

Answer:

The interval of convergence is -1<x<1

Step-by-step explanation:

To find the interval of convergence of the series, we will use the condition for convergence of a series according to Ratio test.

The solution is as shown in the attachment.

7 0

3 years ago

A Letter is Selected from the letters in the word ACCOMMODATION list all the possible types of outcomes

Phantasy [73]

You pick only one letter, so the possible outcomes are:
A,C,O,M,D,T, I, N

if you need to probability of each outcome:
A: 2/13 (there are 2 As and a total of 13 letters)
C: 2/13
O: 3/13

ans so on.
use your calculator to change each fraction to a decimal if needed.

3 0

4 years ago

For X a binomial random variable with n=5 and p=1/4, answer the following

mash [69]

Recall that for $X\sim\mathrm{Bin}(n,p)$ , i.e. a random variable $X$ following a binomial distribution over $n$ trials and with probability parameter $p$ ,

$\mathbb P(X=x)=f_X(x)=\begin{cases}\dbinom nx p^x(1-p)^{n-x}&\text{for }x\in\{0,1,\ldots,n\}\\\\0&\text{otherwise}\end{cases}$

So you have

$\mathbb P(X=2)=\dbinom52\left(\dfrac14\right)^2\left(1-\dfrac34\right)^{5-2}=\dfrac{135}{512}\approx0.26$

$\mathbb P(2\le X\le4)=\displaystyle\sum_{x=2}^4\mathbb P(X=x)$
$=\dbinom52\left(\dfrac14\right)^2\left(1-\dfrac14\right)^{5-2}+\dbinom52\left(\dfrac14\right)^3\left(1-\dfrac14\right)^{5-3}+\dbinom52\left(\dfrac14\right)^4\left(1-\dfrac14\right)^{5-4}$
$=\dfrac{375}{1024}\approx0.37$

The expected value of $X\sim\mathrm{Bin}(n,p)$ is simply $np$ , while the standard deviation is $\sqrt{np(1-p)}$ . In this case, they are $\dfrac54=1.25$ and $\sqrt{\dfrac{15}{16}}\approx0.97$ , respectively.

7 0

3 years ago