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Advocard [28]
3 years ago
6

I’ll mark brainliest

Mathematics
1 answer:
Zolol [24]3 years ago
6 0

Answer:

4, 12

3w=w+8

2w=8

w=4

w+8=4+8=12 (12=3w)

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Will the solutions to the equation 12x2-5x-2=0 be positive or negative and how would you know without solving the equation compl
SOVA2 [1]
For this case we have the following equation:
 12x2-5x-2 = 0
 Using the resolver we have:
 x = (- b +/- root (b ^ 2 - 4 * a * c)) / (2 * a)
 Substituting values we have:
 x = (- (- 5) +/- root ((- 5) ^ 2 - 4 * 12 * (- 2))) / (2 * 12)
 Rewriting:
 x = (5 +/- root (25 +96))) / (2 * 12)
 x = (5 +/- root (121))) / (2 * 12)
 x = (5 +/- 11) / (2 * 12)
 Answer:
 
One root is positive and another is negative.
6 0
3 years ago
Shrek, Donkey, and Fiona are riding in a carriage to Far Far Away. The horses, Prescott and Thaddeus, are pulling the carriage a
Sloan [31]

Answer:

they had more people

Step-by-step explanation:

7 0
3 years ago
Find the difference between 783 and 366
Galina-37 [17]
783-366=417
Difference = Subtraction
8 0
4 years ago
Read 2 more answers
Use substitution to solve the system of equations. 2x+4=32 and -2x-6y= -44
Yakvenalex [24]
The answer is C or D but I think its most definitely C
6 0
3 years ago
Can someone help me and explain step by step
Shkiper50 [21]

Answer:  5) r = 5, 8th term = -78,125

               6) r = 5, 8th term = -312,500

               7) r = 5, {1, 5, 25, 125, 625}

               8) r = 5, {-4, -20, -100, -500, -2500}

<u>Step-by-step explanation:</u>

The explicit formula of a geometric sequence is: a_n=a_1\cdot r^{n-1}, where;

  • n is the number of the term
  • a₁ is the first term
  • r is the common ratio

5)\ a_n=-5^{n-1}\\.\qquad =-1\cdot 5^{n-1}\quad \rightarrow \quad a_1=-1\ and\ r=5\\\\a_8=-5^{8-1}\\.\quad =-5^7\\.\quad =-78,125\\\\\\6)\ a_n=-4\cdot 5^{n-1}\quad \rightarrow \quad a_1=-4\ and\ r=5\\\\a_8=-4\cdot 5^{8-1}\\.\quad =-4\cdot 78,125\\.\quad =-312,500

7)\ a_1=1\ and\ r=5\\.\quad a_2=1\cdot 5=\boxed{5}\\.\quad a_3=5\cdot 5=\boxed{25}\\.\quad a_4=25\cdot 5=\boxed{125}\\.\quad a_5=125\cdot 5=\boxed{625}\\\\\\\\8)\ a_1=-4\ and\ r=5\\.\quad a_2=-4\cdot 5=\boxed{-20}\\.\quad a_3=-20\cdot 5=\boxed{-100}\\.\quad a_4=-100\cdot 5=\boxed{-500}\\.\quad a_5=-500\cdot 5=\boxed{-2500}\\\\\\

8 0
3 years ago
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