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kozerog [31]
3 years ago
6

2x2x2x2x2x2x2x2x2x2x2

Mathematics
2 answers:
-Dominant- [34]3 years ago
6 0

Answer:

i swear that it is 2048

Step-by-step explanation:

i stg if u get it wrong  that is the answer, 2048 this is the freaking answer

iren [92.7K]3 years ago
3 0

\text{Hey there!}

\mathsf{2\times2\times2\times2\times2\times2\times2\times2\times2\times2\times2=2^{11}}

\mathsf{2\times2=4}

\bf{4\times4\times\times4\times4\times4\times2}

\bf{4\times4 = 16}

\mathsf{16\times16\times4\times2}

\bf{16\times16=256}

\text{256}\times4\times2

\bf{256\times4=1,024}

\bf{1.024\times2=answer}

\bf{1,024\times2=2,048}

\boxed{\boxed{\mathsf{Answer: 2,048}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

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4 0
3 years ago
Gwen volunteered to work at the ticket booth for her school's Halloween carnival. The chart below gives the number of hours Gwen
n200080 [17]

A linear relation is a relationship between two variables that when the corresponding pair of values of the variables are plotted, a straight line is obtained

The equation for the relationship between hours Gwen worked and number of tickets is <u> t = </u><u>15·h</u>

<u />

The reason the above equation is correct is as follows:

The given parameters are;

The table of values;

Hours(h): 1, 2, 3, 4

Tickets (t): 15, 30, 45, 60

Required: To write an equation that gives the relation between the number of hours Gwen worked and the number of tickets sold

Solution:

From the given table, we have;

The common difference between successive <em>h-values </em>is 1

The <em>common difference</em> between successive t<em>-values </em>is 30 - 15 = 45 - 30 = 60 - 45 = 15 = Constant

Given that the common difference of the <em>h</em>, and <em>t-values</em> are constant, the relationship is a linear relationship of the form, t = m·h + c

Where;

m = The rate of change of <em>t</em> with <em>h</em>, as follows;

m = (30 - 15)/(2 - 1) = 15

∴ t - 15 = 15 × (h - 1)

t - 15 = 15·h - 15

t = 15·h - 15 + 15 = 15·h

t = 15·h

The equation for the relation between the number of hours Gwen worked and the number of tickets she sold is<u> t = </u><u>15·h</u>

<u />

Learn more about mathematical relationships here:

brainly.com/question/10185505

brainly.com/question/18936577

brainly.com/question/11391605

7 0
2 years ago
At 1 p.m., the number of cars in a parking lot is 78. Given the formula found in the first part of the question, An=78⋅1.09n, es
Harrizon [31]

Answer:

At 6 p.m., the number of cars in a parking lot is 120

Step-by-step explanation:

At 1 p.m., the number of cars in a parking lot is 78.

Given,

A_n=78\cdot 1.09^n

Note that

A_0=78\cdot 1.09^0=78\cdot 1=78

So, 1 p.m. goes for n = 0, then

6 p.m. goes for n = 5

Thus,

A_5=78\cdot 1.09^5\approx 120

4 0
3 years ago
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