I did this but im not very good at it :( but i think the answer is either A or D sorry if im wrong :(
If you're looking to find X, then X would equal 16, since 16 minus 3 would equal 13
The solution depends on the value of

. To make things simple, assume

. The homogeneous part of the equation is

and has characteristic equation

which admits the characteristic solution

.
For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be

. Then

So you have


This means


and so the general solution would be
A is the correct answer.......
Here is the work shown:
x^2-x-20
A is the correct answer because when using the distributive property it is the only example that results in x^2-x-20.
(x+4)(x-5)
x*x=x^2, x*-5=-5x, 4*x=4x, 4*-5=-20. Now combine all alike terms for your final answer. x^2-x-20..
please vote my answer brainliest. thanks!
let x represent the number of apples and y represent the number of oranges.
TOTAL: x + y = 112
y = 112 - x
PEELED: 

3x = 4y
3x = 4(112 - x)
3x = 448 - 4x
7x = 448
x = 64
y = 112 - x
= 112 - 64
= 48
a) There are 64 apples and 48 oranges
Peeled apples:
= 3(8) = 24
Unpeeled apples: 64 - 24 = 40
Unpeeled - Peeled: 40 - 24 - 16
b) there are 16 more unpeeled apples than peeled apples