Based on the trend of the increase in children born out of wedlock, if this trend keeps increasing, the year with 67% of babies born out of wedlock will be 2055 .
<h3>What year will 67% of babies be born to unmarried parents?</h3><h3 />
In 1990, the 28% of children were born out of wedlock and this trend was increasing by 0.6% per year.
If the trend continues, the number of years till 67% of children born out of wedlock will be:
= (67% - 28%) / 0.6%
= 65 years
The year will be:
= 1990 + 65
= 2055
The first part of the question is:
According to the National Center for Health Statistics, in 1990, 28% of babies in the United States were born to parents who were not married. Throughout the 1990s, this percentage increased by approximately 0.6 per year.
Find out more on benefits of marriage at brainly.com/question/12132551.
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500 people took the survey.
12 out of 15 people is 80% of the population. 12/15 = 0.80
Thus, 80% of the population prefers eating in the restaurant.
If 400 represents the people who prefers eating in the restaurant; then, 400 is the 80% of the population. To get the total population or 100%, we must divide 400 by 0.80 or 80%
400 / 0.80 = 500 people.
Out of the 500 people, 400 selected eating in the restaurant while the remaining 20% of the population or 100 people selected cooking at home.
19÷4=4.75
To make it into a percentage, multiply it by 100
4.75×100%=475%
The answer is x².
f(x) = <span>5x - 6
</span>g(x) = x²<span> - 5x + 6
(f + g)(x) = f(x) + g(x)
= </span>5x - 6 + x² - 5x + 6
= x² + 5x - 5x + 6 - 6
= x² + 0 + 0
= x²
4.12 rounded to the nearest tenth is 4.1
