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kow [346]
3 years ago
12

I need help plz my mom is making me do more questions and I need to check them.

Mathematics
2 answers:
Nesterboy [21]3 years ago
7 0
The second one would be 80 square feet. It would be that because square feet is used in area, meaning twice. Multiply 24x2 and 16x2. It would be 48 and 32. When adding them you will get 80.
yuradex [85]3 years ago
4 0
Perimeter of square = 4s perimiter of pentagon= 5s, i guess? its a regular one afterall 4s = P 4 (10) = p 40 = P (40 = 5s)/ 5 8 = s


Sorry I dont know how to answer the second one...

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morpeh [17]

The answer is letter c

7 0
3 years ago
Geometry math question no Guessing and Please show work thank you
nasty-shy [4]

We can name an angle either by naming its vertex or by three letters , keeping the letter of vertex in between.

so here vertex is F

we can name it as ∠EFG, ∠F , ∠GFE

This strikes out the option B that is ∠G

so option B is the answer

6 0
3 years ago
Please help! algebra 1 math! whoever gets right is Brainliest! (10 points)
leva [86]

multiply the 2/3 x the 1/6 to get 1/9

 so the original equation can be rewritten as 3^1/9

 this can be rewritten as the 2nd choice 9cubed3

8 0
3 years ago
I need the answer ....
vladimir1956 [14]

Answer:

12.5 feet

Step-by-step explanation:

how to:

lets find the angle that corresponds with the 10 foot side.

to do that we add 50 degrees plus 90 degrees (right angle) to get 140 degrees.

as we know, a triangles angles will total 180 degrees, so 180 - 140 = 40 degrees for the angle corresponding to the 10 foot side.

put these into ratios:

<u>Angle A  </u>  =    <u>Angle B</u>

side a              side b

now plug in our numbers:

<u>50 degrees</u>     =     <u>40 degrees</u>

        X                       10 feet

Cross multiply:

50 (10 feet) = 40 (x)

solve for x:

500 = 40 (x)

500/40 = x

12.5 = x

<u />

3 0
3 years ago
Etermine two pairs of polar coordinates for the point (2, -2) with 0° ≤ θ &lt; 360°.
Jet001 [13]

To convert from rectangular to polar we will use these 2 formulas:

r^2=x^2+y^2 and

tan\theta=\frac{y}{x}.

The r value found serves as the first coordinate in our polar coordinate, and the angle serves as the second coordinate of the pair. We are told to find 2. Since the r value will always be the same (it's the length of the hypotenuse created in the right triangle we form when determining our angle theta), the angle is what is going to be different in our coordinate pairs. We use the x and y coordinates from the given rectangular coordinate to solve for the r in both our coordinate pairs.

r^2=2^2+ -2^2 which gives us an r value of 2\sqrt{2}. That's r for both coordinate pairs. Now we move to the angle. Setting up according to our formula we have

tan\theta =\frac{-2}{2} =-1.

This asks the question "what angle(s) has/have a tangent of -1?". That's what we have to find out! Since the tangent ratio is y/x AND since it is negative, it is going to lie in a quadrant where x is negative and y is positive, AND where x is positive and y is negative. Those quadrants are 2 and 4. In QII, x is negative so the tangent ratio is negative here; in QIV, y is negative so the tangent ratio is negative here as well. Now, if we type inverse tangent of -1 into our calculators in degree mode, we get that the angle that has a tangent of -1 is -45. Measured from the positive x axis, -45 does in fact go into the fourth quadrant. However, since the inverse tangent of -1 is -45, we also have a 45 degree angle in the second quadrant. Those are reference angles, mind you. A 45 degree angle in QII has a coterminal angle of 135 degree; a 45 degree angle in QIV has a coterminal angle of 315. If you don't understand that, go back to your lesson on reference angles and coterminal angles to see what those are. So our polar coordinates for that rectangular coordinate are

(2\sqrt{2},135) and

(2\sqrt{2},315)

8 0
3 years ago
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