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3 years ago

If u found a briefcase, and the ammount of money was your phone #, how much money did u find?

Mathematics

1 answer:

Maurinko [17]3 years ago

8 0

2720636 muneys :3

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Solve for the value of r.

Furkat [3]

Answer:

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Step-by-step explanation:

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What is the expression in radical form? (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

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4 years ago

Very important question ⁉️

creativ13 [48]

Answer: A △ABC such that the bisectors of ∠ABC and ∠ACB meet at a point O.

To prove :

∠BOC=90

∠A

Step-by-step explanation: In △BOC,

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In △ABC,

∠A+∠B+∠C=180

∠A+2(∠1)+2(∠2)=180

∠A

+∠1+∠2=90

∠1+∠2=90

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∠A

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3 years ago

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