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3 years ago

Calculate the value of angle A and C of ∆ ABC. Where b=1435cm, a= 782cm and B= 115.6°.

Mathematics

1 answer:

Monica [59]3 years ago

5 0

The Law of Sines says

$\dfrac{\sin A}{a} = \dfrac{\sin B}{b} = \dfrac{\sin C}{c}$

$\sin A = \dfrac a b \sin B$

$A = \arcsin( \dfrac{782}{1435} \sin 115.6 ) = 29.44^\circ$

We don't have to worry about the obtuse supplement because a triangle can only have one obtuse angle, and that's B.

$C = 180 - 115.6 - 29.44 = 34.96^\circ$

Answer: A=29.44°, C=34.96°

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We are given with ;

${:\implies \quad \sf \dfrac{33}{2}+\dfrac{3y}{5}=\dfrac{7y}{10}+15}$

Take LCM on both sides :

${:\implies \quad \sf \dfrac{165+6y}{10}=\dfrac{7y+150}{10}}$

Multiplying both sides by 10 ;

${:\implies \quad \sf \cancel{10}\times \dfrac{165+6y}{\cancel{10}}=\cancel{10}\times \dfrac{7y+150}{\cancel{10}}}$

${:\implies \quad \sf 165+6y=7y+150}$

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Transposing 6y to LHS and 150 to RHS

${:\implies \quad \sf 7y-6y=165-150}$

${:\implies \quad \bf \therefore \quad \underline{\underline{y=15}}}$

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Calculate the value of angle A and C of ∆ ABC. Where b=1435cm, a= 782cm and B= 115.6°.​

Calculate the value of angle A and C of ∆ ABC. Where b=1435cm, a= 782cm and B= 115.6°.