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lisov135 [29]
3 years ago
9

Mason has a candy bar into 12 equal pieces he eats one third of the candy bar has brother eats 1/4 of the candy bar and he saves

the rest of his candy bar for later what fraction of candy bar does Mason save for later
Mathematics
2 answers:
Ksenya-84 [330]3 years ago
6 0
He saved 5/12 of the candy bar

sleet_krkn [62]3 years ago
5 0
Mason saves 5/12 or the bar for later. Get a common denominator then subtract your numerator or top number. 


12/12 = 1 candy bar
1/3 x 4/4 = 4/12
1/4 x 3/3 = 3/12
12/12 - 7/12 = 5 /12
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3 0
3 years ago
Read 2 more answers
Heather was asked to graph 2x + 4y = 12 by using slope and y-intercept. Her graph is shown.
blagie [28]
The problem statement says "the graph is shown," but you haven't shared it.  Please do that if possible.  Thank you.

<span>Heather was asked to graph 2x + 4y = 12 by using slope and y-intercept.

We can quickly put this into slope-intercept form:  
                                                                                                 12 - 2x
Subtract 2x from both sides:  2x - 2x + 4y = 12 - 2x  =>   y = ------------ 
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In simplest form, this is y = 3 - (1/2)x, or (-1/2)x + 3.  The slope is -1/2 and the y-intercept is (0,3).</span>
6 0
3 years ago
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The equation of the hyperbola that has a center at ( 6 , 9 ) , a focus at ( 11 , 9 ) , and a vertex at ( 9 , 9 ) (x−C)^2/A^2−(y−
MrMuchimi

Answer:

A=-3

C=6

B=4

D=9

Step-by-step explanation:

From the question we are told that:

Center of hyperbola at ( 6 , 9 )

Focus of hyperbola at ( 11 , 9 )

Vertex of hyperbola at ( 9 , 9)

Equation of hyperbola \frac{(x-C)^2}{A^2} -\frac{(y-D)^2}{B^2}=1

Generally the C and D of the hyperbola equation is mathematically given by

Centers (6,9)

C=6

D=9

Generally the A and B a of the hyperbola equation is mathematically given by

 A=x_c-x_v

 A=6-9

 A=-3

 C'=x_c-x_f

 C'=6-11

 C'=-5

Therefore with Center,Focus ,Vertex on the same line

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 B^2=16

 B=4

3 0
3 years ago
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