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Kobotan [32]
3 years ago
14

A post card collector has 1,230 postcards if she displays them on pages that hold 6 cares each how many pages does she need ?

Mathematics
1 answer:
Snezhnost [94]3 years ago
5 0
There are 1230 postcards
each page can hold 6 cards

so your equation is 

1230/6 =x 

where as x is the pages she needs 

x = 205

She needs 205 pages exactly

hope this helps
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What is the surface area of the composite figure
leva [86]

Answer:

The answer is 672.

Step-by-step explanation:

To solve this problem, first let's find the surface area of the rectangular prism. To do that, multiply each dimension with each (times 2 | just in case you don't understand [what I'm talking about is down below]).

8 x 8 x 2 = 128

8 x 11 x 2 = 176

8 x 11 x 2 = 176

Then, add of the products together to find the surface area of the rectangular prism.

176 + 176 + 128 = 480

Now, let's find the surface area of the square pyramid. Now, for this particular pyramid, let's deal with the triangles first, then the square. Like we did with the rectangular prism above, multiply each dimension with each other (but dividing the product by 2 | in case you don't understand [what i'm talking about is down below]).

8 x 8 = 64.

64 ÷ 2 = 32.

SInce there are 4 triangles, multiply the quotient by 4 to find the surface area of the total number of triangles (what i'm talking about is down below).

32 x 4 = 128.

Now, let's tackle the square. All you have to do is find the area of the square.

8 x 8 = 64.

To find the surface area of the total square pyramid, add both surface areas.

128 + 64 = 192.

Finally, add both surface areas of the two 3-D shapes to find the surface area of the composite figure.

192 + 480 = 672.

Therefore, 672 is the answer.

6 0
3 years ago
Please help fast.
podryga [215]

\huge{\underline{\boxed{\tt{Answer:}}}}

Let AB be a chord of the given circle with centre and radius 13 cm.

Then, OA = 13 cm and ab = 10 cm

From O, draw OL⊥ AB

We know that the perpendicular from the centre of a circle to a chord bisects the chord.

∴ AL = ½AB = (½ × 10)cm = 5 cm

From the right △OLA, we have

OA² = OL² + AL²

==> OL² = OA² – AL²

==> [(13)² – (5)²] cm² = 144cm²

==> OL = √144cm = 12 cm

Hence, the distance of the chord from the centre is 12 cm.

━═━═━═━═━═━═━═━═━━═━═━═━═━═━

8 0
3 years ago
A pharmacist has 40% and 60iodine solutions on hand. How many liters of each iodine solutions will be required to produce 4 lite
Schach [20]

A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine mixture?

.

Let x = liters of 40% iodine

then

4-x = liters of 80% iodine

Using algebra:

.40x + .80(4-x) = .50(4)

.40x + 3.20-.80x = 2

3.20-.40x = 2

x = 4 liters (40% iodine)

80% iodine:

4-x = 4-4 = 0 liters needed (80% iodine)

4 0
3 years ago
What is the domain of the following graph?
Morgarella [4.7K]

Answer:

[0,9]

Step-by-step explanation:

The domain is the first set of the ordered pair. When finding the domain you are supposed to find which x value it starts from to where it ends. The x value starts from 0 and ends and the 9th unit on the x-axis which would give us 0,9 now since both points are closed you would use these symbols [ ] to show that it is closed meaning the answer would be [0,9]

Note:

I'm sorry if this is wrong but this is what I believe the answer is.

4 0
3 years ago
Please answer correctly, im giving 45 points and brainliest. You get like 25 points
Aleonysh [2.5K]

c. Roller Rink F charges 1.00 more per person than roller rink G.

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3 years ago
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