Answer:
The probability is 0.3576
Step-by-step explanation:
The probability for the ball to fall into the green ball in one roll is 2/1919+2 = 2/40 = 1/20. The probability for the ball to roll into other color is, therefore, 19/20.
For 25 rolls, the probability for the ball to never fall into the green color is obteined by powering 19/20 25 times, hence it is 19/20^25 = 0.2773
To obtain the probability of the ball to fall once into the green color, we need to multiply 1/20 by 19/20 powered 24 times, and then multiply by 25 (this corresponds on the total possible positions for the green roll). The result is 1/20* (19/20)^24 *25 = 0.3649
The exercise is asking us the probability for the ball to fall into the green color at least twice. We can calculate it by substracting from 1 the probability of the complementary event: the event in which the ball falls only once or 0 times. That probability is obtained from summing the disjoint events: the probability for the ball falling once and the probability of the ball never falling. We alredy computed those probabilities.
As a result. The probability that the ball falls into the green slot at least twice is 1- 0.2773-0.3629 = 0.3576
Answer: 5000000000
Step-by-step explanation: i just know
<span>lengths are in ratio 1:3
areas are in ratio
1 : 3</span>²<span> = 1: 9
area of ADG = 9 x 42 = 378 </span>
<span>This isn't very difficult to figure out, you just need to look at these numbers in pairs. So, 16 minus 4 is 12. Then the next pair of numbers, 36 minus 9 is 27. And to complete the pattern, you just have to look at the final pair: 44 minus 11 is 33. So the number that would complete the pattern is 33.Hope this helps. Let me know if you need additional help!</span>
