The cosine of angle y would be equal to the length of the adjacent side over the length of the hypotenuse.
cos(y) =
=
(2x + 7)(x - 5) = 2x² - 10x + 7x - 35 = 2x² - 3x - 35
Answer:
Hello! After reading your question I have deduced that the correct answer is 288² cm.
Step-by-step explanation:
The way I came to this conclusion was as follows:
Firstly:
If said rectangle is two squares put side by side (adjacent), then a valid assumption is that both squares are the same size.
This is because all four sides of a square have to be equal.
Thus if the two squares are joined together on one side, then all the other sides of both the squares will be the same length.
Thus both of the squares are going to be the same size, so they will have the same area.
Secondly:
If the area of one square is 144² cm then the area of the other square should also be 144² cm.
Thus if you combine the areas of both the squares, that make up the rectangle, you are left with the area of the rectangle being 288² cm.
I hope this helped!
9514 1404 393
Answer:
- parallel: y = x -1
- perpendicular: y = -x -3
Step-by-step explanation:
The given line has a rise of 1 for each run of 1, so a slope of 1. If you draw a line with a slope of 1 through the given point, you can see that it intersects the y-axis at y = -1. Then the slope-intercept equation is ...
y = x -1 . . . . . equation of parallel line
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The perpendicular line will have a slope that is the opposite reciprocal of the slope of the given line: m = -1/1 = -1
A point that is 1 unit right and 1 unit down from the given point is -3 on the y-axis. This is the y-intercept of the perpendicular line. The equation is ...
y = -x -3 . . . . . equation of perpendicular line
Answer:
The current supplies the maximum wattage is 6 Ampere.
Step-by-step explanation:
Given : In a 120-volt circuit having a resistance of 10 ohms, the power W in watts when a current I is flowing through is given by
To find : What current supplies the maximum wattage?
Solution :
The equation of power is
Derivate w.r.t x,
For critical point put it to zero,
Now, again derivate w.r.t I,
It is maximum at I=6 A
Therefore, the current supplies the maximum wattage is 6 Ampere.