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3 years ago

Can someone just help me with number 1 and 2

Mathematics

1 answer:

natta225 [31]3 years ago

8 0

Answer:

dummy

Step-by-step explanation:

you are stupid

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Volume of cone round to the nearest 10th

guapka [62]

Answer: 63

Maybe?

If it’s wrong sorry :)

4 0

3 years ago

HELP I NEED HELP ASAP

Kaylis [27]

Answer:

so how many units are they away from each other

Step-by-step explanation:1,

1.1-2.0 how many units are they away from each other

u could drag the number from the top to the chart below

good luck!

6 0

3 years ago

I'll give you brainliest if you answer correctly! <3

NeTakaya

Answer:

The answer should the second Arrow option.

Step-by-step explanation:

I'm not into this subject well so, <em>so sorry if its wrong</em>..

This type of test is in K12 which is my school.

8 0

2 years ago

How to differentiate y=x^n using the first principle. In this question, I cannot use the rule of differentiation. I have to do t

Zarrin [17]

By first principles, the derivative is

$\displaystyle\lim_{h\to0}\frac{(x+h)^n-x^n}h$

Use the binomial theorem to expand the numerator:

$(x+h)^n=\displaystyle\sum_{i=0}^n\binom nix^{n-i}h^i=\binom n0x^n+\binom n1x^{n-1}h+\cdots+\binom nnh^n$

$(x+h)^n=x^n+nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n$

where

$\dbinom nk=\dfrac{n!}{k!(n-k)!}$

The first term is eliminated, and the limit is

$\displaystyle\lim_{h\to0}\frac{nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n}h$

A power of $h$ in every term of the numerator cancels with $h$ in the denominator:

$\displaystyle\lim_{h\to0}\left(nx^{n-1}+\dfrac{n(n-1)}2x^{n-2}h+\cdots+nxh^{n-2}+h^{n-1}\right)$

Finally, each term containing $h$ approaches 0 as $h\to0$ , and the derivative is

$y=x^n\implies y'=nx^{n-1}$

4 0

3 years ago

Simplify 1.25 (-x -4)

maw [93]

Answer:

-1.25x-5

Step-by-step explanation:

5 0

2 years ago