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larisa [96]
4 years ago
11

Graph the system equation 2x - y = 4 x - y= -2

Mathematics
1 answer:
Ipatiy [6.2K]4 years ago
8 0
Hello there!


You need to look for a calculator on the internet that can do that.

I used demos, it is not bad!


As always, it is my pleasure to help people like you!

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Solve the equation 1/3(x−10)=-41/3(x−10)=-4
Furkat [3]

so hard.but i will help you

5 0
3 years ago
Can some one help me find the code?
NISA [10]
Piper and sawyer reposted it for you uu
7 0
3 years ago
Fairly easy, im just not the smartest. <br><br> There wasn't a section btw
Mkey [24]

Answer:

1. Stellar nebula

2. white dwarf

3. Average Mass star

4. Red Giant

5. Planetary Nebula

im not sure it thats correct tho but

hope this helps

have a good day :)

Step-by-step explanation:

8 0
3 years ago
Help me with this problem please right away​
svlad2 [7]

Answer:

6\frac{1}{2} = A

Step-by-step explanation:

The first step is to use the Distance Formula to figure out the lengths of the two legs:

\sqrt{[-x_1 + x_2]^{2} + [-y_1 + y_2]^{2}} = D

R(1, 1) and P(−1, −2) ↷

\sqrt{[1 + 1]^{2} + [2 + 1]^{2}} = \sqrt{2^{2} + 3^{2}} = \sqrt{4 + 9} = \sqrt{13}\\ \\ \sqrt{13} = RP

Q(2, −4) and P(−1, −2) ↷

\sqrt{[1 + 2]^{2} + [2 - 4]^{2}} = \sqrt{[-2]^{2} + 3^{2}} = \sqrt{4 + 9} = \sqrt{13} \\ \\ \sqrt{13} = QP

* So, by my calculations, we have an isosceles <em>right triangle</em>, and according to the <em>45°-45°-90° triangle theorem</em>, we automatically know that the hypotenuse, <em>RQ</em>, is \sqrt{26}:

30°-60°-90° triangle theorem

2x, x, x√3

↑ ↑ ↑

h leg leg

y

p

o

t

e

n

u

s

e

45°-45°-90° triangle theorem

x√2, x, x

↑ ↑ ↑

h legs

y

p

o

t

e

n

u

s

e

So now, we have to find the area of the triangle by taking half of either height or base, then multiplying that by the height or base, but since this is an isosceles <em>right</em><em> </em><em>triangle</em><em>,</em><em> </em>it does not matter:

[\frac{h}{2}][b] = A \: \:OR\: \: [\frac{b}{2}][h] = A \: \:OR \: \: \frac{hb}{2} = A

[\frac{\sqrt{13}}{2}][\sqrt{13}] = \frac{13}{2} = 6\frac{1}{2} \\ \\ 6\frac{1}{2} = A

I am joyous to assist you anytime.

8 0
3 years ago
Lines are drawn through the point (2, 8) and the points given below. Select two points that correspond with lines with negative
aleksley [76]
Since the slope is (change in y)/(change in x), and a negative number over a positive number is negative (and vice versa), we want to figure that out. Therefore, we would want 2 to be bigger than the x value and 8 smaller than the y value, or the other way around. (0,9) fits the description, as well as (5, 6)
5 0
3 years ago
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