Answer:
f(x) = -3x + 12
Step-by-step explanation:
The chart could be represented like this:
x y
0 12
1 9
2 6
3 3
Suppose that f(x) = y
And substitute x values.
y = -3x + 12
"x = 0"
y = -3(0) + 12
y = 0 + 12
y = 12
"x = 3"
y = -3(3) + 12
y = -9 + 12
y = 3
From the results, it corresponds to the function.
Answer:
you have to start at the zero figure number which would be (-6) and go up 3 but sideways only once each time if that makes scene.
Step-by-step explanation:
1. (2r + 9)(2r-9) = 4r^2 -81
+ (2r - 9)^2 = 4r^2 - 36r + 81
= 8r^2 - 36r
2. 12 - 5 [ a^2 + a - 1 ] + 5a
= 12 - 5a^2 - 5a + 5 +5a
= 17 - 5a^2
x^3 + 3x^2 + 6x + 18
______
3. x-3/ x^4 + 7
- ( x^4 - 3x^3)
----------------
3x^3 + 7
- (3x^3 - 6x^2)
-------------------
6x^2 + 7
- (6x^2 - 18x)
-------------------
18x + 7
- (18x - 54)
--------------
7 + 54 = R = 61
welp That's What I get
(12x+13)2 hope this helps
NB- Solution is emboldened
import java.util.Scanner;
import java.util.Random;
public class RandomGenerateNumbers {
public static void main (String [] args) {
Random randGen = new Random();
int seedVal = 0;
seedVal = 4;
randGen.setSeed(seedVal);
System.out.println(randGen.nextInt(50) + 100);
System.out.println(randGen.nextInt(50) + 100);
return;
}
}
