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GenaCL600 [577]
4 years ago
10

PLEASE PLEASE HELP! Referring to the diagram above, predict what will happen when the switch is closed. Explain your answer.

Physics
1 answer:
IgorC [24]4 years ago
8 0

the batteries would heat up due to the over load of power not going into any thing and the screw driver is giving it a boost of energy



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How do materials, such as nutrients and waste, pass through the cell membrane?
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Think of the cell membrane as a net and the nutrients are the perfect fit to fall through it. Where the waste is not the right size and will not fit through the holes of the net.
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What happens to the resource when competition for it increases
aniked [119]
I’d say it would go away
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3 years ago
a wrench weighs 5.24 newtons on earth. when it is taken to the Moon, where g =1.16 m/s2 how much does it weigh?
Andrew [12]

“Weight of the wrench” on “the moon” is “6.07 kg”.

<u>Explanation</u>:

Weight of the wrench is 5.24 N  

Weight of the wrench in kilograms = W × g

Taken “g” on the moon is 1.16 \mathrm{m} / \mathrm{s}^{2}

=5.24 \mathrm{N} \times 9.81 \mathrm{m} / \mathrm{s}^{2}=51.352 \mathrm{kg}

Weight of the wrench in kilograms is 51.352 kg.

Formula to calculate weight of the object on the moon is

\frac{\text {weight of the object on earth}}{9.81 \mathrm{m} / \mathrm{s}^{2}} \times 1.16 \mathrm{m} / \mathrm{s}^{2}

Substitute the values given,

=\frac{51.352 \mathrm{kg}}{9.81 \mathrm{m} / \mathrm{s}^{2}} \times 1.16 \mathrm{m} / \mathrm{s}^{2}

=5.234 \times 1.16

= 6.07 kg

Therefore, weight of the wrench on the moon is 6.07 kg.  

6 0
3 years ago
ASK YOUR TEACHER A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 51.5-gram mass is attach
Simora [160]

Answer:

0.114 kg or 114 g

Explanation:

From the diagram attaches,

Taking the moment about the fulcrum,

sum of clockwise moment = sum of anticlockwise moment.

Wd = W'd'

Where W = weight of the mass, W' = weight of the meter rule, d = distance of the mass from the fulcrum, d' = distance of the meter rule.

make W'  the subject of the equation

W' = Wd/d'................ Equation 1

Given: W = mg = 0.0515(9.8) = 0.5047 N, d = (39.2-16) = 23.2 cm, d' = (49.7-39.2) = 10.5 cm

Substitute these values into equation 1

W' = 0.5047(23.2)/10.5

W' = 1.115 N.

But,

m' = W'/g

m' = 1.115/9.8

m' = 0.114 kg

m' = 114 g

6 0
3 years ago
Security is a major concern now that computers play such a large part in healthcare. To address this concern, as well as others
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The correct answer is C. HIPAA

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4 years ago
Read 2 more answers
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