4. A plane traveling at 200 m/s drops supplies from 1500 m above the ground. If it reaches

Physics

1 answer:

NikAS [45]3 years ago

4 0

Answer:

3500 m

Explanation:

To find the horizontal displacement of the box of supplies, we just need to analyze its horizontal motion.

The horizontal motion of the box is a uniform motion with constant velocity, since there are no forces acting along this direction. Therefore, the horizontal displacement is given by

$d=v_x t$

where

$v_x$ is the horizontal velocity

t is the time

The horizontal velocity of the supplies is the same as the plane, therefore

$v_x = 200 m/s$

So, since the time of flight is

t = 17.5 s

The horizontal displacement is

$d=(200)(17.5)=3500 m$

You might be interested in

Find the current i in:

lawyer [7]

Answer:

I = 24 A

Explanation:

This is Parallel Circuit and it is the first principle of parallel circuit that voltage will be equal in all components in the circuit

It includes 10 resistors Therefore the voltage across,

R1 = R2 = R3 = R4 = R5 = R6 = R7 = R8 = R9 = R10 = voltage in battery

We will apply Ohm's Law to each resistor to find its current because we know the voltage across each resistor is 12 V and the resistance of each resistor is 5Ω

I (R1) = E (R1) / R1

I (R1) = 12v / 5Ω

I (R1) = 2.4 A

The value resistance E of all resistors are same therefore by applying the formula above the value of current in all resistors will be 2.4 A

The Total current in the circuit will be

I (total) = I (1) + I (2) + I (3) + I (4) + I (5) + I (6) + I (7) + I (8) + I (9) + I (10)

I (total) = 2.4 + 2.4 + 2.4 + 2.4 + 2.4 + 2.4 + 2.4 + 2.4 + 2.4 + 2.4

I (total) = 24 A

5 0

3 years ago

A capacitor consists of two metal surfaces separated by an insulating layer. A new capacitor has no charge on either of its surf

mihalych1998 [28]

<h2>Answer:</h2><h3>(A) the positively charged surface increases and the energy stored in the capacitor increases.</h3>

When charging a capacitor transferring charge from one surface to the other, the first surface becomes negatively charged while the second surface becomes positively charged. As you transfer the charge, the voltage of the positively charged surface increases and the energy stored in the capacitor also increases. We can solve this by the definition of <em>capacitance</em><em> </em>that is <em>a measure of the ability of a capacitor to store energy. </em>For any capacitor, the capacitance is a constant defined as:

$C=\frac{Q}{V_{ab}}$