Answer:
2,400 minutes and its is 144,000 secods
Step-by-step explanation:
Answer:
WX = 11
Step-by-step explanation:
We know that VX is the full line segment.
We also know that VX = 14.
There is a point W on the line segment.
From this we know that the length of VW = 3.
To solve for WX we have to figure out how much distance is in between W and X.
To do this we have to simply subtract 3 from 14.
14 - 3= 11
Thus, we know that WX = 11.
Answer:
A
Step-by-step explanation:
To move something up or down, it means we're moving along the y-axis. So we need to change the y-coordinate.
To move it up, we'll be moving towards the positive end of the y-axis. On a coordinate plane, if you move anything "up," you're moving closer to the positive end of the y-axis.
To move it five units up, we need to move 5 units positively.
So our y is:
y + 5
To move something left or right, it means we're moving it along the x-axis. So we need to change the x-coordinate.
To move it left, we'll be moving it towards the negative end of the x-axis. Think about it: on a basic number line (which is what the x-axis is), the more you move towards the left, you move closer to 0, and therefore the negative end.
To move it 2 units left, we need to move 2 units negatively.
So our x is:
x - 2
Putting them together, we have:
(x, y)
(x - 2, y + 5)
Answer:
idk how to do this
Step-by-step explanation:
440 gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antifreeze
<em><u>Solution:</u></em>
Let "x" be the gallons of 80 % antifreeze added
Therefore, "x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze
Final mixture is x + 80
Therefore, we can frame a equation as:
"x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get (x + 80) gallons of 70 % antifreeze
Thus, we get,
x gallons of 80 % + 80 gallons of 15 % = (x + 80) gallons of 70 %
![x \times \frac{80}{100} + 80 \times \frac{15}{100} = (x+80) \times \frac{70}{100}\\\\0.8x + 80 \times 0.15 = (x+80) \times 0.7\\\\0.8x+12 = 0.7x+56\\\\0.8x-0.7x=56-12\\\\0.1x = 44\\\\x = \frac{44}{0.1}\\\\x = 440](https://tex.z-dn.net/?f=x%20%5Ctimes%20%5Cfrac%7B80%7D%7B100%7D%20%2B%2080%20%5Ctimes%20%5Cfrac%7B15%7D%7B100%7D%20%3D%20%28x%2B80%29%20%5Ctimes%20%5Cfrac%7B70%7D%7B100%7D%5C%5C%5C%5C0.8x%20%2B%2080%20%5Ctimes%200.15%20%3D%20%28x%2B80%29%20%5Ctimes%200.7%5C%5C%5C%5C0.8x%2B12%20%3D%200.7x%2B56%5C%5C%5C%5C0.8x-0.7x%3D56-12%5C%5C%5C%5C0.1x%20%3D%2044%5C%5C%5C%5Cx%20%3D%20%5Cfrac%7B44%7D%7B0.1%7D%5C%5C%5C%5Cx%20%3D%20440)
Thus 440 gallons of 80 % antifreeze solution must be mixed