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irina [24]
2 years ago
9

6. Solve each equation by graphing. Round to the nearest tenth. x2 - 6x= -8

Mathematics
1 answer:
Neko [114]2 years ago
6 0

The answer is for this question is A

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Solve for y<br> 2(3 + 3y) + y = 11
garik1379 [7]
<h2><u>EQUATION</u></h2><h3>Exercise</h3>

2(3 + 3y) + y = 11

First, apply the distributive property:

2(3 + 3y) + y = 11

6 + 6y + y = 11

6 + 7y = 11

Substract 6 from both sides:

6 - 6 + 7y = 11 - 6

7y = 5

Divide both sides by 7:

\dfrac{7y}{7} = \dfrac{5}{7}

\boxed{y = \dfrac{5}{7}}

<h3><u>Answer</u>. The value of y = 5/7.</h3>

8 0
2 years ago
PLZ help fast I need this I’ll give brainliest
rodikova [14]

Answer:

1. 2

2.circle

3.b tan t

Step-by-step explanation:

5 0
3 years ago
Write the exponential equation for this scenario. Mike buys a car for $45,000.00. The cars value depreciates (loses value) at a
gladu [14]

Answer:

A=45000(0.82)^t

Step-by-step explanation:

Given data

P= 45,000

rate= 18%

Recall the expression for the compound interest

A=P(1+r)^t

Since we are talking of depreciation

A=P(1-r)^t

Substitute

A=45000(1-0.18)^t\\\\A=45000(0.82)^t

Hence the exponential function is

A=45000(0.82)^t

6 0
2 years ago
Give two different sequences of three transformations that would map PQR onto EFG given that PQR=EFG.
Gre4nikov [31]

9514 1404 393

Answer:

  1. Translate P to E; rotate ∆PQR about E until Q is coincident with F; reflect ∆PQR across EF
  2. Reflect ∆PQR across line PR; translate R to G; rotate ∆PQR about G until P is coincident with E

Step-by-step explanation:

The orientations of the triangles are opposite, so a reflection is involved. The various segments are not at right angles to each other, so a rotation other than some multiple of 90° is involved. A translation is needed in order to align the vertices on top of one another.

The rotation is more easily defined if one of the ∆PQR vertices is already on top of its corresponding ∆EFG vertex, so that translation should precede the rotation. The reflection can come anywhere in the sequence.

__

<em>Additional comment</em>

The mapping can be done in two transformations: translate a ∆PQR vertex to its corresponding ∆EFG point; reflect across the line that bisects the angle made at that vertex by corresponding sides.

3 0
2 years ago
Read 2 more answers
Question 7
Ksenya-84 [330]

Answer:

(4,2) and (2,-2)

Step-by-step explanation:

using m=y2-y1/x2-x1

m= -2-2/2-4=-4/-2

therefore,

m=2

3 0
2 years ago
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