<h3>
Answer: x = 14</h3>
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Work Shown:
Refer to the diagram below. I've added a line segment and two variables y and z. This forms two isosceles triangles.
The central angle 56 degrees subtends the same arc as the inscribed angle y. By the inscribed angle theorem, this means y = 56/2 = 28. The inscribed angle is always half of the central angle (when both angles subtend the same arc).
Focus on the smaller isosceles triangle that has angles 56, z and z. Those three angles add to 180
z+z+56 = 180
2z+56 = 180
2z = 180-56
2z = 124
z = 124/2
z = 62
Now focus on the larger isosceles triangle (angles y = 28, x+z and x+z)
We'll use the same trick as before.
(x+z)+(x+z)+(y) = 180
(x+62)+(x+62)+(28) = 180 ... plug in z = 62 and y = 28
2x+152 = 180
2x = 180-152
2x = 28
x = 28/2
x = 14
The points on the graph are:
- Midline point = (0,-5)
- Maximum point = (0.65,-2)
<h3>(a) The graph of the function</h3>
The equation of the function is given as:
See attachment for the graph of the function f(x)
<h3>(b) The midline point</h3>
This is the point that is on the line that passes through the midsegment of the function.
From the graph, a point on the midline is (0,-5)
<h3>(c) The maximum point</h3>
This is the point that is on the vertex of the function.
From the graph, a point on the midline is (5pi/24,-2)
This can be rewritten as: (0.65,-2)
Read more about trigonometry graphs at:
brainly.com/question/8120556
Answer:
2.5(x-1)+4.5(-x-2)
2.5x-2.5-4.5x-9
-2x-11.5
Step-by-step explanation:
Answer:
Step-by-step explanation:
Sampling Variability
Hope that helped! :)
Answer:
3 times
Explanation:
We know that:
small diameter = 2 * 10^-2 in
large diameter = 6 * 10^-2 in
We want to know how many times larger is the thin diameter compared to the large one.
We will do this as follows:
large diameter = k * small diameter
where k is the number of times that we want to find
6 * 10^-2 = k * 2 * 10^-2
k = (6 * 10^-2) / (2 * 10^-2)
k = 3
This means that the large diameter is 3 times the small one.
Hope this helps :)
