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Alex Ar [27]
3 years ago
6

Fluffy the cat is 3 years older than Scuffy the dog. Six less than five times Scruffy's age is one more than three times Fluffy'

s age. How old is each animal?
Mathematics
1 answer:
lesya692 [45]3 years ago
6 0

Answer: fluffy is 11 years old

Scuffy is 8 years old

Step-by-step explanation:

Let x represent the present age of Fluffy the cat.

Let y represent the present age of Scuffy the dog.

Fluffy the cat is 3 years older than Scuffy the dog. This means that

x = y + 3 - - - - - -- - - - - 1

Six less than five times Scruffy's age is one more than three times Fluffy's age. This means that

5y - 6 = 3x + 1

5y - 3x = 1 + 6

5y - 3x = 7 - - - - - - - - - -2

Substituting equation 1 into equation 2, it becomes

5y - 3(y + 3) = 7

5y - 3y - 9 = 7

5y - 3y = 7 + 9

2y = 16

y = 16/2 = 8

x = y + 3

x = 8 + 3 = 11

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Step-by-step explanation:

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X - 3/2 = 3. Please show your work. Will mark BRAINLIEST
BARSIC [14]

\huge\text{Hey there!}

\mathsf{x-\dfrac{3}{2}=3}

\large\textsf{You have to SIMPLIFY the SIDES of   The  given EQUATION}

\mathsf{x + (-\dfrac{3}{2}) = 3}

\large\textsf{ADD by } \mathsf{\dfrac{3}{2}}\large\textsf{ to BOTH  of the SIDES}

\mathsf{x + (-\dfrac{3}{2})+ \dfrac{3}2{}=3+\dfrac{3}{2}}

\large\textsf{CANCEL out: } \mathsf{-\dfrac{3}{2}+\dfrac{3}{2}}\large\textsf{ because that gives you 0}  

\large\textsf{Keep: } \mathsf{3+ \dfrac{3}{2}}\large\textsf{ because that helps solve for your x-value }

\large\textsf{New equation: }\mathsf{x = 3 + \dfrac{3}{2}}

\mathsf{3+\dfrac{3}{2}}

\large\textsf{SOLVE above and you have your ANSWER}

\mathsf{3+\dfrac{3}{2}=\bf \dfrac{9}{2}}

\boxed{\boxed{\large\textsf{Therefore, your answer is: }\mathsf{\bf x = \dfrac{9}{2}}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

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D

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For this one, you want to solve it similarly to linear equations.

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From there, you divide by 11 to isolate x, leaving x<1.

Since the equation has a < symbol (not ≤), the dot is not filled in. X is less than 1, so the arrow goes to the left, making it D.

**This content involves solving and sketching linear inequalities, which you may wish to revise. I'm always happy to help!

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