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Alex Ar [27]
3 years ago
6

Fluffy the cat is 3 years older than Scuffy the dog. Six less than five times Scruffy's age is one more than three times Fluffy'

s age. How old is each animal?
Mathematics
1 answer:
lesya692 [45]3 years ago
6 0

Answer: fluffy is 11 years old

Scuffy is 8 years old

Step-by-step explanation:

Let x represent the present age of Fluffy the cat.

Let y represent the present age of Scuffy the dog.

Fluffy the cat is 3 years older than Scuffy the dog. This means that

x = y + 3 - - - - - -- - - - - 1

Six less than five times Scruffy's age is one more than three times Fluffy's age. This means that

5y - 6 = 3x + 1

5y - 3x = 1 + 6

5y - 3x = 7 - - - - - - - - - -2

Substituting equation 1 into equation 2, it becomes

5y - 3(y + 3) = 7

5y - 3y - 9 = 7

5y - 3y = 7 + 9

2y = 16

y = 16/2 = 8

x = y + 3

x = 8 + 3 = 11

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The value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Given the equation y=16-x^{2} and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16-x^{2} from x=-1 to x=1.

Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.

Integration is basically opposite of differentiation.

y=16-x^{2}

Find the integration of 16-x^{2}.

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Hence the value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Learn more about integration at brainly.com/question/27419605

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