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Alex Ar [27]
3 years ago
6

Fluffy the cat is 3 years older than Scuffy the dog. Six less than five times Scruffy's age is one more than three times Fluffy'

s age. How old is each animal?
Mathematics
1 answer:
lesya692 [45]3 years ago
6 0

Answer: fluffy is 11 years old

Scuffy is 8 years old

Step-by-step explanation:

Let x represent the present age of Fluffy the cat.

Let y represent the present age of Scuffy the dog.

Fluffy the cat is 3 years older than Scuffy the dog. This means that

x = y + 3 - - - - - -- - - - - 1

Six less than five times Scruffy's age is one more than three times Fluffy's age. This means that

5y - 6 = 3x + 1

5y - 3x = 1 + 6

5y - 3x = 7 - - - - - - - - - -2

Substituting equation 1 into equation 2, it becomes

5y - 3(y + 3) = 7

5y - 3y - 9 = 7

5y - 3y = 7 + 9

2y = 16

y = 16/2 = 8

x = y + 3

x = 8 + 3 = 11

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Answer:

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Step-by-step explanation:

We use the section formula:

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We substitute the point A(-1.5,0) and B(4.5,8).

We plug in the points to get:

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This is supposed to be equal to: (0,2).

(\frac{4.5m - 1.5n}{m+n},\frac{8m+n \times 0}{m+n}) = (0,2)

We can equate, corresponding coordinates to find m and n.

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This implies that:

4.5m - 1.5n = 0

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\frac{m}{n}  =  \frac{1}{3}

Therefore the ratio is m:n=1:3

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