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ICE Princess25 [194]
3 years ago
5

What is the average rate of change for this exponential function for the interval from x=2 to x=4?

Mathematics
2 answers:
wariber [46]3 years ago
7 0

Use slope for (y2-y2/x2-x1) to find the average slope.

Plug 4 into the function. The answer is y2 (4 is x2)

Plug 2 into the function. The answer is y1 (2 is x1)

(y2 - y1)/ (4 - 2)

(y2 - y1)/2

That is how you would get the average rate of change.

mario62 [17]3 years ago
5 0

The equation to calculate the average rate of change is: y/x

y = f(x2) - f(x1)x = x2 - x1

x1: 1 (The smaller x value. It can be any number)x2: 2 (The larger x value. It also can be any number)f(x1): The value when you plug x1 into the function.f(x2): The value when you plug x2 into the function.

If we know this, the variables for this problem are assuming the function is 10(5.5)^x:

x2: 2x1: 1f(x2): 10(5.5)^(2) = 302.5f(x1): 10(5.5)^(1)= 55

This means:y = 302.5  - 55 = 247.5x = 2 - 1 = 1

Remember: the equation for avg rate of change is y/x

So, our average rate of change for the function on the interval [1,2] is 247.5 (y/x = 247.5/1)

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Answer:

Carl traveled 281.25 km by bus and 1,618.75 km by plane.

Step-by-step explanation: v1 = 60 km/h average speed by bus to Toronto

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t = 7 h total traveling time

t1 = the time of the travel by bug

t2 = the time of the travel by plane

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d1 = the distance traveled by bus

d2 = the distance traveled by plane

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Since average speed = distance/time we have time = distance/avg.speed

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t2 = d2/v2 that is t2 = d2/700

Plug the above values into t1 + t2 = t.

We have the following system of equations:

d1/60 + d2/700 = 7

d1 + d2 = 1900

.......

Click here to see the step by step solution for 'd1' and 'd2'

.......

d1 = 281.25 km

d2 = 1,618.75 km

Carl traveled 281.25 km by bus and 1,618.75 km by plane.


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