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goldenfox [79]
3 years ago
9

Hector got 12 out of 20 words right in a spelling test what percentage did he get wrong

Mathematics
2 answers:
statuscvo [17]3 years ago
5 0

Answer:

8%

Step-by-step explanation:

enot [183]3 years ago
4 0

Answer:

60% is the answer

Step-by-step explanation:

it becomes 3/5 then 6/10 and 6/10 = 60%

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How do you work the problem 6752-3827 to get the answer​
Anestetic [448]

Answer:

you subtract and get 2925

Step-by-step explanation:

6 0
3 years ago
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How much does 4 5/7 kg of candy cost if 5/6 kg costs $7.50
Aliun [14]

Answer:

It costs $42.43

Step-by-step explanation:

Lets explain how to solve the problem

- The cost of \frac{5}{6} kilogram of candy is $7.5

- We need to find the cost of 4\frac{5}{7} kilogram

We  can use the ratio to find the answer

======= Dollar   :    Kilogram

======= 7.5        :    \frac{5}{6}

=======  c           :    4\frac{5}{7}  

By using cross multiplication

∴ c × \frac{5}{6} = 7.5 × 4\frac{5}{7}

∵ 4\frac{5}{7} = \frac{4*7+5}{7}

∴ 4\frac{5}{7} = \frac{33}{7}

∴ c × \frac{5}{6} = 7.5 × \frac{33}{7}

∴ c × \frac{5}{6} = \frac{495}{14}

Divide both sides by \frac{5}{6}

∴ c = \frac{495}{14} ÷ \frac{5}{6}

Change the division sign to multiplication sign and reciprocal the

fraction after the division sign

∴ c = \frac{495}{14} × \frac{6}{5}

∴ c = \frac{297}{7} = 42.43 dollars

∵ c represents the cost of 4\frac{5}{7} kg

∴ It costs $42.43

7 0
3 years ago
Calculus Problem
Roman55 [17]

The two parabolas intersect for

8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2

and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

a. Square cross sections will contribute a volume of

\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x

where ∆x is the thickness of the section. Then the volume would be

\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x

We end up with the same integral as before except for the leading constant:

\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx

Using the result of part (a), the volume is

\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x

and using the result of part (a) again, the volume is

\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}

7 0
2 years ago
DESCRIBE HOW TO WRITE 3 DIGIT NUMBERS IN THREE DIFFERENT WAYS
victus00 [196]
Just put each number in different positions.
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how many different burritos can be made when a customer chooses one item frm each category shown in the table
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Answer:13

Step-by-step explanation:

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