Answer:
Step-by-step explanation:
Algebraic expressions tend to have atleast one unknown variable in it. In order to solve the expression we need to assign a fixed value to that variable or isolate it if the expression is equal to another value. For example, in the following expression we have the variable x, if we give it a value of 5 we simply solve like a regular expression...
5x + 3
5(5) + 3
25 + 3
28
Therefore, if we swap the variable x for the value of 5 we would get a value of 28 in this algebraic expression.
Answer:
domain: (-5, infinity)
range: (-infinity, 2)
Step-by-step explanation:
A(n) = a₁.(r)ⁿ⁻¹, where a₁ = 1st term, r= common ratio and n, the rank
In the formula given a₁ = 5, r = 3/2 and n = 6 (we have to find the 6th term value).
a₆ = 5.(3/2)⁶⁻¹ = 5.(3/2)⁵ = 1215/32 (answer C)
Set up two equations:
Greg = 330 + 75X
Heather = 660 + 45x
Set them to equal and solve for x:
330 + 75x = 660 + 45x
Subtract 330 from both sides:
75x = 330 + 45x
Subtract 45x from both sides:
30x = 330
Divide both sides by 30:
x = 330 / 30
X = 11
11 months they will have the same amount saved.
Answer:
C. g has been shifted down five units and to the left two units from f
Step-by-step explanation:
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