All categories

2 years ago

What is the value of r in the equation? Negative 1. 5 (4 minus r) = negative 12 –6 –4 4 6.

Mathematics

1 answer:

Debora [2.8K]2 years ago

5 0

Answer:

-458

Step-by-step explanation:

-1.5(4 - r) = -12 - 6 -446

-6 + r = -464

r = -458

You might be interested in

Thomas and his sister Lauren are competing in a running race. When Thomas is 0.7 miles from the finish line, he notices that his

ratelena [41]

Answer:

ummmmm 0.825

Step-by-step explanation:

im pretty sure thats correct i havent done math like that in a while let me know if its right :)

4 0

2 years ago

How do I divide whole numbers by fraction? (Ex: 12 ÷ 1⁄2)

Readme [11.4K]

That would be 6 just put the the whole number over one and keep flip change

7 0

2 years ago

Read 2 more answers

STUDY TIP 1

Mandarinka [93]

Answer:

THANK U!

FOR THE TIP.

HAVE A GREAT DAY!

6 0

2 years ago

Is there a way to find figure out a function with just the X & Y intercepts. I know there are convertors to find the X &

AlladinOne [14]

Answer:

Step-by-step explanation:

yes, since that are 2 points:

y-int is (0, y)

x-int is (x, 0)

since you need only two points for a function with no restrictions, we can use y and x intercepts as points

3 0

3 years ago

H(x) = x2 1 k(x) = x – 2 (h k)(2) = (h – k)(3) = Evaluate 3h(2) 2k(3) =.

natima [27]

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.The value of the given functions are,

$(h+k)(x)=5$

$(h-k)(x)=9$

$3h(2)+2k(3)=17$

<h3>Given information-</h3>

The given function is,

$h(x)=x^2+1$

$k(x)=x-2$

<h3>Quadratic equation</h3>

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.

1) The value of the function (h+k)(2),

$(h+k)(x)=h(x)+k(x)$

$(h+k)(x)=x^2+1+x-2$

$(h+k)(2)=2^2+1+2-2$

$(h+k)(x)=5$

2)The value of the function (h-k)(3),

$(h-k)(x)=h(x)-k(x)$

$(h-k)(x)=x^2+1-x+2$

$(h-k)(3)=3^2+1-3+2$

$(h-k)(x)=9$

3) The value of the function 3h(2)+2k(3)

$3h(x)+2k(x)=3x^2+3+2x-2\times 2$

$3h(2)+2k(3)=3\times2^2+3+2\times2-2\times 2$

$3h(2)+2k(3)=17$

Hence the value of the given functions are,

$(h+k)(x)=5$

$(h-k)(x)=9$

$3h(2)+2k(3)=17$

Learn more about the quadratic equation here;

brainly.com/question/2263981

4 0

2 years ago