Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z = 
~ N(0,1)
where, 
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P( > 
) = P(Z > 1.25) = 1 - P(Z 
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Answer:
x^3 - 3x^2 +2x
Step-by-step explanation:
Use the distributive property
Answer:
c = 1, f = 5, and r = 1
Step-by-step explanation:
5(1)/(5) = 1/(1)
5/5 = 1/1
1 = 1
Answer: see last picture
Step-by-step explanation:
We see that the y-intercept is 10 and the slope is -3
so when x = 0, y = 10
Graph this first point (picture 1)
Since the slope is -3, every time you go one unit to the left, you go down 3 units, so graph this second point (picture 2)
Continue this until you have no more room on the graph (picture 3)
now draw a line through the dots (picture 4)
Answer:
x=1 y=-5
Step-by-step explanation:
7(5x-2y=15) ---> 35x-14y=105
2(7x+7y=-28) --> + <u>14x+14y=-56</u>
49x=49 --->x=1
5(1)-2y=15 ---> 5-2y=15 ---> -2y=10 ---> y=-5
