Answer:
the lowest passing score would be x = 298
Step-by-step explanation:
School wishes that only 2.5 percent of students taking test pass
We are given
mean= 200,
standard deviation = 50
We need to find x
The area under the curve can be found by:
2.5 % = 0.025
So, 1- 0.025 = 0.975
We need to find the value of z for which the answer is 0.975
Looking at the z-score table, the value of z is: 1.96
Now, using the formula:
z = x - mean/standard deviation
1.96 = x - 200/50
=> 1.96 * 50 = x-200
98 = x - 200
=> x = 200+98
x = 298
So, the lowest passing score would be x = 298
Answer:
i agree
Step-by-step explanation:
jdkfhkjdf jajxjcj jdf o
assuming 
Then the column values for base five here are
5³ 5² 
We can get 1 × 5³ = 125 → 219 - 125 = 94
We can get 3 × 5² = 75 → 94 - 75 = 19
We can get 3 x → 19 - 15 = 4
and 4 = 4 ×
Thus = 
As a check
(1 × 125 ) + (3 × 25 ) + (3 × 5 ) + 4 = 219
14.29 * .0725 = 1.04
1.04 * 3 = 3.12
