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vichka [17]
3 years ago
11

Double Points! Write an inequality that models a real-world situation. Describe your situation and what the variable x represent

s. Thank you! Bad/fake answers will be reported.
Mathematics
2 answers:
Morgarella [4.7K]3 years ago
3 0

A child planted five beans. How many bean plants will grow? x equals the number of bean plants that will grow. There will not be more than five plants, but there could be less if not all of the beans grow.

X is less than or equal to 5

X ≤ 5


Diano4ka-milaya [45]3 years ago
3 0

Answer:

You can take the following example:

Rick earns $50 a day. For how many days should he work so he earns no less than $750.

It can be solved as follows:

Let the number of days Rick should work be = x

He earns $50 a day, so for x days he will earn 50x.

Now, his earnings cannot be less than $750. We can show this as follows:

50x\geq 750

We will solve for x now.

x\geq 750/50

x\geq 15

This means here that Rick will have to work for at least 15 days to get $750. If he will work less than 15 days, he will get less money.

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Charlie puts $50000 in a stock account, but it loses money at a rate of 20%
Alina [70]

Answer:

You dind't include the answer choices but it should look something like

50000(.8)^t

4 0
3 years ago
The table below shows data for a class's mid-term and final exams:
lina2011 [118]
Mid term :
Q1 = (88 + 85)/2 = 86.5
Q2 = (92 + 95)/2 = 93.5
Q3 = 100
IQR = Q3 - Q1 = 100 - 86.5 = 13.5

final exams :
Q1 = (65 + 78)/2 = 71.5
Q2 = (88 + 82)/2 = 85
Q3 = (95 + 93)/2 = 94
IQR = Q3 - Q1 = 94 - 71.5 = 22.5

so the final exams has the largest IQR
 
5 0
3 years ago
Read 2 more answers
In trapezoid $ABCD$, $\overline{AB}$ is parallel to $\overline{CD}$, $AB = 7$ units, and $CD = 10$ units. Segment $EF$ is drawn
Mekhanik [1.2K]

Answer:

EF = 58/7

Step-by-step explanation:

If you extend both BC and AD to meet at P you get 3 similar triangles PAB, PEF, and PCD. Let's call BF = 3x and FC = 4x. Therefore the following proportions can be expressed:

BP/7 = (BP+7x)/10

10BP = 7*(BP+7x)

10BP = 7BP+49x

3BP = 49x

BP = (49/3)x

BP/7 = (BP+3x)/EF

EF = (BP+3x)*7/BP

EF = ((49/3)x + 3x)*7/((49/3)x)

EF = ((58/3)x*7*3)/(49x)

EF = 58/7

3 0
3 years ago
50 POINTS! I MARK BRAINLEST AND SAY THANKS!
Phantasy [73]
Y *x =20

y +x =9

rewrite 1st eq. as y = 20/x

subsituute that into 2nd eq.

20/x +x =9

multiply each term by X

20 +x^2 = 9x
 subtract 9x from each side:

x^2 - 9x +20 = 0

now factor:

(x-5) (x-4) = 0

solve for x
5-5 = 0
 4-4 = 0

so X can be 4 or 5

replace x into equations and solve for Y

 so when X = 4, Y = 5
 When X = 5, Y = 4

x= 5,4
y = 4,5



5 0
4 years ago
Read 2 more answers
Help me pleaseeeeeee
nikklg [1K]

Answer:

y=-2x-6

Step-by-step explanation:

6 0
3 years ago
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