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LenKa [72]
3 years ago
6

Find the domain and range of the INVERSE of the given function. Square root x-3

Mathematics
1 answer:
Ulleksa [173]3 years ago
4 0
f(x)=\sqrt{x-3}\\
y=\sqrt{x-3}\\
y^2=x-3\\
x=y^2+3\\
f^{-1}(x)=x^2+3\\
D:x\in\matxbb{R}\\
R:y\in\langle3,\infty)
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Simplify <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B6%5D%7B5%7D%20%20%5Ctimes%20%20%5Csqrt%5B2%5D%7B5%7D%20%20%3D%20" id
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\sqrt[6]{5}  \times  \sqrt[2]{5}

=  {5}^{  \frac{1}{6}  }  \times  {5}^{ \frac{1}{2} }

=  {5}^{ \frac{1}{6} +  \frac{1}{2}  }

=  {5}^{ \frac{1 + 3}{6} }

=  {5}^{ \frac{4}{6} }

=  {5}^{ \frac{2}{3} }

=  \sqrt[3]{ {5}^{2} } (ans)

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