One number be x
x+(x+1)+(x+2)=63
x+x+1+x+2=63
3x+3=63
3x=63-3
3x=60
x=60:3
x=20
smallest number = x=20
middle <span>number = x+1= 20+1=21
</span>largest<span><span><span> number = x+2</span> =20+2= 22</span>
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4/(x+1) = 3/x + 1/15
Should we make common denominators with everything, we get
4*15*x / [15x(x+1)] = 3*15*(x+1)/[15x(x+1)] + x(x+1)/[15x(x+1)]
Multiply both sides of the equation by the denominator to cancel them
60x = 45(x+1) + x(x+1)
60x = 45x + 45 + x^2 + x
x^2 - 14x + 45 = 0
(x-9)(x-5) = 0
The answer to this question is that the solutions are x=9 and x=5.
9.014 , 9.789 , 9.991
Good luck
<span>ow far does the first car go in the 2 hours head start it gets?
Now, at t = 2 hours, both cars are moving. How much faster is the second car than the first car? How long will it take to recover the head start? You can determine this by dividing the head start by the difference in the two speeds. If car 1 has a 20 mile head start, and car 2 is 5 mph faster, then it will take 20/5 = 4 hours to catch up.
</span>You could also write two equations, one for each car, showing how far they have gone in a variable amount of time. Set the two equations equal to each other and solve for the value of the time. Note that the second car's equation will use (t-2) for the time, because it doesn't start driving until t = 2.
Answer:a) a=22, b=11
b) m=7
, n= 
Step-by-step explanation:
You should use trigonometry ratios as required and then you should use pythagoras theorem
In a) cosine(30°)= base/hypotenuse,
where 11√3 is the base
"a" is hypotenuse and
"b" is perpendicular
from this you can find the value of perpendicular then you should use pythagoras theorem to find the value of hypotenuse
pythagoras theorem is
base²+perpendicular²= hypotenuse²
Same is applied on (b) right triangle as, sine(45°)=perpendicular/hypotenuse
