The three broad classes of elements are:
Metals
Metalloids
Nonmetals
Answer:
6g O2
Explanation:
Mole to mole ratio:
A balanced chemical equation shows a chemical reaction while maintaining the law of conservation of mass. The coefficients of the substances are known to be very helpful in computations as they represent the equivalent amounts of moles of the species that would be participating in the reaction.
We set up the chemical equation and then find the balanced chemical expression.
S+O2→SO3
Balance
2S+3O2→2SO3
We use the following values for the variables:
mS=4.0 gm
We proceed with the solution.
mO2= 4 g S × 1 mol S/ 32 g S × 3 mol O2/ 2 mol S × 32g O/ 1 mol O2
mO2 = 6 g
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Hi the answer is 100x I hope that helps
Answer:
Many hydrocarbons are found in plants, animals, and their fossils; other hydrocarbons have been prepared in the laboratory. We use hydrocarbons every day, mainly as fuels, such as natural gas, acetylene, propane, butane, and the principal components of gasoline, diesel fuel, and heating oil.